Both cylinder are similar
Volume of a cylinder is πr^2h
if we consider both has same radius as they are similar
Lets say V1 is volume of small cylinder and V2 is volume of big cylinder.
V1/V2=πr^2x5/πr^2xh
125/343=5/h
0.36=5/h
h=5/0.36
h=13.72 ft
The measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
<h3>How to determine the
measure of
angle EBF?</h3>
The angle measures are given as
If m ∠ A B F = ( 8 w − 6 ) ° m ∠ A B E = [ 2 ( w + 11 ) ] ° m ∠ E B F
Rewrite the angle measures properly.
This is done, as follows
m∠ABF = (8w − 6)°
m∠ABE = [2(w + 11)]
The measure of angle m∠EBF is calculated as:
m∠ABF = m∠ABE + m∠EBF
Substitute the known values in the above equation
8w - 6 = 2(2w + 11) + m∠EBF
Open the brackets
8w - 6 = 4w + 22 + m∠EBF
Evaluate the like terms
m∠EBF = 4w - 28
Hence, the measure of angle EBF where he angle measures are given as m∠ABF = (8w − 6)° and m∠ABE = [2(w + 11)] is m∠EBF = 4w - 28
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3x - 2y = 5 is linear
linear equations will not have exponents
Answer:

Step-by-step explanation:
We have 36 characters in total which we can use in order to form a 6 character password.
For each place in this password we have choice of 36 of them, so, the total number of possible passwords of 6 characters is:

But, we have to exclude all passwords which have no numbers because, by the task, the password must contain at least one digit.
So, now we have choice of 26 characteristic to form password without digits and get
passwords like that, contained just of letters without digits.
So, the final answer is that we have
6-character passwords with at least one digit.
Answer:
93
Step-by-step explanation:
So, you basically basic math it, or calculator.