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aksik [14]
3 years ago
15

Create an expression to find the time for the given distance and rate, and find the value of the expression. 

Mathematics
1 answer:
marysya [2.9K]3 years ago
5 0
Note the equation/formula:
____________________________
      
         d * r = t  ;
_____________________________
  in which:  
_____________________________
        d = distance = 84 ft.
        r  = rate = 12 ft / sec
       <span> t  = time = ?</span>
_______________________________
To find the "time" we can rearrange the equation:
_______________________________________
       d = r * t  ;   
_______________________________________
   Divide EACH SIDE of the equation by "r" ;  to isolation "t" on one side of the equation; to create an expression to find the time for the given distance and rate; which we will then do by plugging in our given values for "d" (distance) and "r" (rate) ;
_______________________________________
     d / r = (r * t) / r ;  
_________________________
 to get :   d / r = t ; 
_________________________
         ↔   t = d / r  ;
_________________________
Now, plug in our given values for "d" and "r" ; to solve for "t" ;
______________________________________________________
        →    t = 84 ft / (12 ft / sec) ; 
   
                  =  84 ft   ÷    ;
    
                  =  84 ft  *   ;
  
                  =  {   }  sec. ; 
  
                    →   t    =   7 sec.   {that is;  "7 seconds" }
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Answer:

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Step-by-step explanation:

let the number = x

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2 years ago
PLEASE HELP! IM ALMOST DONE !
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Answer:

D. \frac{22x + 48}{x^2 - 36}

Step-by-step explanation:

Given:

\frac{15}{x - 6} + \frac{7}{x + 6}

Required:

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Solution:

Add both fractions

Thus,

\frac{15}{x - 6} + \frac{7}{x + 6}

\frac{15(x + 6) + 7(x - 6)}{x^2 - 36}

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Therefore,

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3 years ago
The sum of squares of three consecutive numbers is 77 find the numbers​
ollegr [7]

Answer:

4,5,6 are the three consecutive numbers. 16, 25 and 36 are their squares.

Step-by-step explanation:

Let the three consecutive numbers be x, (x+1), (x+2)

Now, the squares of these three numbers are  x^{2} ,(x+1)^{2} ,(x+2)^{2}

Sum = 77

∴by the problem ,

x^{2} +(x+1)^{2}+(x+2)^{2}  = 77\\x^{2} +(x^{2} +2x+1)+(x^{2}+4x +4) = 77\\x^{2} +x^{2} +2x+1+x^{2} +4x +4 = 77\\3x^{2} +6x+5 = 77\\3x^{2} +6x = 77-5\\3x^{2} + 6x = 72\\3x^{2} +6x-72= 0\\

{Taking 3 common }

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{By factorization}

x^{2} +2x- 24 =0\\ x^{2} +6x-4x-24=0\\x(x+6)-4(x+6)=0\\(x+6)(x-4)=0\\

Therfore,

x= -6,4\\

<em>X can't be negetive </em>

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The squares of the three consecutive numbers are 16, 25, 36

The three consecutive numbers whose sum is 77 are 4, 5, 6

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