Answer:
Given
Step-by-step explanation:
Given that: △RST ~ △VWX, TU is the altitude of △RST, and XY is the altitude of △VWX.
Comparing △RST and △VWX;
TU ~ XY (given altitudes of the triangles)
<TUS = <XYW (all right angles are congruent)
<UTS ≅ <YXW (angle property of similar triangles)
Thus;
ΔTUS ≅ ΔXYW (congruent property of similar triangles)
<UTS + <TUS + < UST = <YXW + <XTW + <XWY = 
(sum of angles in a triangle)
Therefore by Angle-Angle-Side (AAS), △RST ~ △VWX
So that:
= 
(corresponding side length proportion)
Answer:
4000
Step-by-step explanation:
Answer:
Step-by-step explanation:
put it on a coorinate grid,
circle circumference = 2*pi*r = 100.53
so the arc 19.2/100.53 = about 0.15 times the circumference of the circle
0.15*2pi = angle AOB in radians = 0.97
length DE is like 7.44
angle DOE is approx 0.485 radians beacuse it's half of angle AOB
area of shaded region is 804.2477 probably. I'm not sure about this last one sorry I think my calculator messed up
The answer is C, as both numbers are only both divisible by 1.
