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Sedbober [7]
3 years ago
11

The definition of a circle uses the undefined term _______

Mathematics
1 answer:
Kay [80]3 years ago
7 0

Answer:

plane because i know what it is                                                                                                  

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Can someone please help me with this!!!!
balandron [24]
You can use the similarity approach of these two triangles CBD and CAE

as a result:
\frac{BD}{AE} = \frac{10}{2x} = \frac{CD}{CE} = \frac{3x}{?}

so:
? = 6x^2 / 10 = 0.6 x^2

and the fact of:

"The segment connecting the midpoints of two sides of a triangle is parallel to the third side and equals its half length"

so:BD = 0.5 AE        10 = 0.5 * 2x        >>> x= 10


Back to:
? =0.6 x^2 = 0.6 * 10^2 = 0.6 * 100 = 60



A

Hope that helps
7 0
3 years ago
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A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the loud
salantis [7]
C.2.52 is your answer
7 0
3 years ago
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PPPPPPPLLLLLLLLZZZZZZ HELP I AM GIVING BRAINLIEST AND 50 POINT
azamat
#4: The data is symmetric, which means it is C. NOT SKEWED

#3: Adding the outlier will not change the median, but it will decrease the mean. So the answer is B.
4 0
3 years ago
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A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
3 years ago
The price of Stock A at 9 A.M. was​ $15.75. Since​ then, the price has been increasing at the rate of​ $0.05 per hour. At​ noon,
tatyana61 [14]

Answer: I think is 3.5

Step-by-step explanation:

7 0
3 years ago
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