A)
x = -y -2
y = -x -2
B)
0.5x + y = 1
0.5x + (-x -2) = 1
-0.5x -2 = 1
-0.5x = 3
x = -6
The reaction is missing and it's ;
N2H4 + H2 ---> 2NH3
It asks for the total pressure too.
Answer:
A) Rate of change for NH3 = 152 torr/h
B) The total pressure in the vessel will remain the same.
Step-by-step explanation:
N2H4 + H2 ---> 2NH3
1 mole of N2H4 yields 2 moles of NH3.
From the question, the rate given for N2H4 is 76 torr/h.
Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h
Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.
While on the product side, 2 moles of NH3 are produced.
So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.
I think this is a repeat question from yesterday.
f(x)=3x+1
g(x)=x^2-1
f o g (x) = f(g(x))=f(x^2-1)=3((x^2-1))+1=3x^2-3+1=3x^2-2
f o g(2)=3(2^2)-2=3(4)-2=10
Answer: 250ft3
Step-by-step explanation:
v=l*w*H
v= 10*5 * 5
v=250
