Question

Plzzz Helpp with this!!!!

Answer 1

f(g(11)) = -6

Solution:

Given data:

$f(x)=x^{2}-6 x+3$

$g(x)=\sqrt{x-2}$

To find f(g(11)):

Substitute x = 11 in g(x).

$g(11)=\sqrt{11-2}$

        $=\sqrt{9}$

$g(11)=3$

Substitute g(11) = 3 in f(g(11)).

$f(g(11))=f(3)$

$f(x)=x^{2}-6 x+3$

$f(3)=3^{2}-6 (3)+3$

$f(3)=9-18+3$

$f(3)=-6$

$f(g(11))=f(3)$

             = -6

Hence f(g(11)) = -6.