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kramer
3 years ago
8

Plzzz Helpp with this!!!!

Mathematics
1 answer:
Travka [436]3 years ago
6 0

f(g(11)) = -6

Solution:

Given data:

f(x)=x^{2}-6 x+3

g(x)=\sqrt{x-2}

<u>To find f(g(11)):</u>

Substitute x = 11 in g(x).

g(11)=\sqrt{11-2}

        =\sqrt{9}

g(11)=3

Substitute g(11) = 3 in f(g(11)).

f(g(11))=f(3)

f(x)=x^{2}-6 x+3

f(3)=3^{2}-6 (3)+3

f(3)=9-18+3

f(3)=-6

f(g(11))=f(3)

             = -6

Hence f(g(11)) = -6.

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The given function is f(x) = 200·(1.05)ˣ

1. The initial population is given by the value of the function when x = 0,

which is given as follows;

At x = 0, f(0) = 200·(1.05)⁰ = 200

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2. The rate of growth of the fish from the exponential function is given as follows;

The growth factor = 1.05

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3. Please find attached the graph of the exponential function created

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The asymptote of the exponential function is the line, <u>y = 0</u>

The table of values is presented as follows;

\begin{array}{|c|c|c}x&f(x)\\0&200 & y-intercept\\1&210\\3&231.525\\4&243.1\\5&255.26\end{array}

4. The domain is the possible x-values which is; 0 ≤ x < ∞

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Which gives;

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  • Range: [200, ∞)

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f(11) = 200 × (1.05)¹¹ ≈ 342

  • The population of the fish after 11 years is <u>346 (fishes)</u>

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