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sladkih [1.3K]
4 years ago
14

Using the digits 0 to 9 at most one time each,fill in the boxes below to write equations whose solution is -1/2

Mathematics
1 answer:
Lena [83]4 years ago
3 0

Answer:

The equations whose solutions are -1/2 are:

1. 4x + 1 = 6x + 2

2. 3x + 7 = 5x + 8

Step-by-step explanation:

Using the digits 0 to 9 at most one time each, the equations whose solutions are -1/2 are:

1. 4x + 1 = 6x + 2

-2x = 1

x = -1/2

2. 3x + 7 = 5x + 8

-2x = 1

x = -1/2

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Using the sum of the years digits method

Step 1:

We sum up all the digits of the estimated life of equipment.

i.e. 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 210

Step 2:

We count the years spent from the back. i.e. year 2 is equivalent to 19 in the years digits.

Given that the cost of the equipment is $79,600.00 with a salvage value of $4,000.00. This means that the depreciable amount of the equipment is given by $79,600.00 - $4,000.00 = $75,600.00

The depreciation charge on the equipment for year 1 is given by

\frac{20}{210} \times\$75,600=\$7,200

while the depreciation charge on the equipment for year 2 is given by

\frac{19}{210} \times\$75,600=\$6,840

The book value of an equipment is given by the cost of the equipment minus the accumulated depreciation.

Therefore, the book value of the equipment at the end of year 2 is given by

$79,600 - $7,200 - $6,840 = $65,560
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4 years ago
Use the given equation to complete the table: s = 16 t squared t (sec) s(ft) 0 1 2 3 Using the points from the table select the
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Step-by-step explanation:

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What is this question pls?
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Answer:

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Step-by-step explanation:

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James measured a piece of construction paper to be 6 3/4 inches wide and 9 2/3 inches long. What is the area of the piece of con
ivolga24 [154]

Answer:

The area of the piece of construction paper is \frac{261}{4} inches^2

Step-by-step explanation:

Length of construction paper =6 \frac{3}{4} inches

                                                 =\frac{27}{4} inches

Width of construction paper = 9 \frac{2}{3} inches

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Area of construction paper =Length \times Width

Area of construction paper = \frac{27}{4}  \times \frac{29}{3}

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