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2 years ago

Please help figure this out with the correct words

Mathematics

1 answer:

mr Goodwill [35]2 years ago

5 0

Answer:

pyramids only have one base.

Step-by-step explanation:

polygon base

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Is of I ready please help me ?

blsea [12.9K]

Answer: N has to be a negative. hope this helps

Step-by-step explanation:

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3 years ago

Which table does not represent a function?

andrew-mc [135]

the correct option is answer choice D, because there are multiple 2's in the x column with different f(x) values.

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3 years ago

In a game, the probability that a spinner will land on blue is 1/4. How many times would you expect to land on blue if you spin

JulijaS [17]

Answer:

2 times

Step-by-step explanation:

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3 years ago

The sum of two integers is 121. The larger integer is 7 more than twice the smaller integer. Find the two integers.

iren [92.7K]

X + (2x + 7) = 121 : Write the expression.
3x + 7 = 121 : Combine like terms.
3x + 7 - 7 = 121 - 7 : Isolate x.
3x = 114 : Combined like terms.
3x / 3 = 114 / 3 : Find the value of x.
x = 38 : This is the smaller integer.
(2x + 7) = (2(38) + 7) = 76 + 7 = 83. : Find the value of the larger number by plugging in the value of x to the larger number's quantity.
The larger number is 83, and the smaller number is 38.

5 0

3 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago