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Solnce55 [7]
3 years ago
7

A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and al

l of the digits can be repeated?
The Options are:
A. 10 × 96
B. 9 × 107
C. 9 × 106
D. 107
Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0

Answer:

9 \cdot 10^6

Step-by-step explanation:

A phone number contains 7 digits. How many different numbers can be made using the digits 0–9 if the first digit is not 0 and all of the digits can be repeated

In 7 digit phone number, the first number cannot be 0

So only 1  to 9 are used to get the first digit. 9 numbers can be used

other digits can use number from 0 to 9. 10 number can be used

So possible numbers can be made is

9 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10 \ times \ 10

9 \cdot 10^6

IRISSAK [1]3 years ago
6 0

I do believe c but idk

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Answer:

the correct answer is D

Step-by-step explanation:

because the -9 5/8 is in absolute value marks.

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3 years ago
5(x-7) = 6(x+2)<br>please help ... I got 11x = -23??​
eimsori [14]

Answer:

x = -47

Step-by-step explanation:

1. Use the distributive property

5 ( x - 7 ) = 6 ( x + 2 ) → 5x - 35 = 6x + 12

2. Subtract 5x from both sides of the equation

5x - 5x -35 = 6x - 5x + 12 → -35 = x + 12

3. Subtract 12 from both sides

-35 - 12 = x + 12 - 12 → -47 = x

4. So, the answer is

x = -47

4 0
3 years ago
The table below shows the distance a car travels and the amount of gasoline left in the tank of the car.
Fynjy0 [20]

Answer:22478

Step-by-step explanation:

5 0
3 years ago
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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).
Alexeev081 [22]
Zeros are the x values which make the function equal to zero. Set it up as you would for a binomial with a constant multiplier "k" to account for the y-intercept (0, -5) given.

f(x) = k(x-2)(x-3)(x-5)

Use the y-intercept (0,-5) to solve for k.

-5 = k(0-2)(0-3)(0-5)
-5 = -30k
-5/-30 = k
1/6 = k


The cubic polynomial function is then ..

f(x) = (1/6)(x-2)(x-3)(x-5)
 

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5 0
3 years ago
Read 2 more answers
How to solve by factoring 16x^=121
VMariaS [17]
-------------------------------------------------------
Equation Given :
-------------------------------------------------------
16x² = 121

-------------------------------------------------------
Take away 121 from both sides:
-------------------------------------------------------
16x² - 121 = 0

-------------------------------------------------------
Make each term a perfect square
--------------------------------------------------------
(4x)² - (11)² = 0

--------------------------------------------------------
Apply algebraic rule : a² - b² = (a + b)(a - b)
--------------------------------------------------------
(4x + 11) (4x - 11) = 0

-------------------------------------------------------
Apply zero product property :
-------------------------------------------------------
4x + 11 = 0 or 4x - 11 = 0

--------------------------------------------------------
Solve for x :
--------------------------------------------------------
4x = - 11 or 4x = 11
x = -11/4 or x =11/4

--------------------------------------------------------------------------
Answer: x = -11/4 or x = 11/4
--------------------------------------------------------------------------
5 0
3 years ago
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