Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]
The intersection of sets R and D is give by the following set:
R ∩ D = {3, 9, 15}.
<h3>What is the missing information?</h3>
This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.
<h3>What is the set that is the intersection of two sets?</h3>
The set that is the intersection of two sets is composed by the elements that belong to both sets.
For this problem, the sets are given as follows:
- R = {1,3,5,7,9,11,13,15,17}.
- D={3,6,9,12,15,18,21,24,27}
Hence the intersection is given by:
R ∩ D = {3, 9, 15}.
As the elements 3, 9 and 15 are the only ones that belong to both sets.
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Answer:
Step-by-step explanation:
$15 × 0.75 × 1.04 = $11.70
$25 × 0.75 × 1.04 = $19.50
$37 × 0.75 × 1.04 = $28.86
$65 × 0.75 × 1.04 = $50.70
Answer:
what are the other drop down menus
Step-by-step explanation:
Answer:
(4 + 7i)(4 – 7i)
Step-by-step explanation:
This pair will produce a real answer because they are complex conjugates.
Complex conjugates ( a+bi) (a-bi) when multiplied together form a real number ( a^2 + b^2)
For statictics of Out of 780 smokers, 376 have been divorced, Non-smokers: Out of 2855 non-smokers, 902 have been divorced, the 95% confidence interval for smokers and non-smokers is mathematically given as
- 95% confidence interval = (0.5352, 0.4462)
- 95% confidence interval = (0.3424, 0.2894)
- 53% increased risk of divorce for smokers.
<h3>What is the 95% confidence interval for smokers and non-smokers?</h3>
Generally, the equation for the Confidence interval is mathematically given as
p ± Z/2[p(1-p)]/n
Where
Z1/2=1-(0.05/2)
Z1/2=0.975
Read z table we have
Z score= 1.96
Hence
0.4907 ± 1.96 (0.4907)(1-0.4907)/485
0.4907±0.0445
Therefore
95% confidence interval = (0.5352, 0.4462)
b)
Z1/2 = 1- (0.05/2)
Z1/2 = 0.975
Z score= 1.96
0.3159 ± 1.96 (0.3159)(1-0.3159)/1184
0.3159±0.0265
Thereofore
95% confidence interval = (0.3424, 0.2894)
c)
In conclusion, The 95% confidence interval helps us read that 53% increased risk of divorce for smokers.
Read more about Confidence interval
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