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NARA [144]
3 years ago
12

What would the vertices be?

Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
Two straight lines or edges intersect
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(Fog)(x) where f(x)=1/x^2+3 and g(x)= square root x-2
Sati [7]

Answer:

(fog)(x) = 1/(x-2) + 3

Step-by-step explanation:

f(x) = 1/x² +3        g(x) = √(x-2)

(fog)(x) = f(g(x)) = f( √(x-2)) = 1/(√(x-2))² +3

(fog)(x) = 1/(x-2) + 3

5 0
3 years ago
5y - 10 = -25 <br> A) y = 3 B) y = 7 C) y = -3 D) y = -7
Setler79 [48]

Answer:

C

Step-by-step explanation:

5 * -3 = -15 - 10 = -25

7 0
4 years ago
Read 2 more answers
If f(x) = x-1 and g(x) =2x-3 find the sum, difference, product and quotient of these two functions
victus00 [196]
We have the following functions:
 f (x) = x-1
 g (x) = 2x-3

 For the sum we have:
 f (x) + g (x) = (x-1) + (2x-3)
 f (x) + g (x) = 3x - 4

 For subtraction we have:
 
f (x) - g (x) = (x-1) - (2x-3)
 f (x) - g (x) = -x + 2

 For  the product we have:
 
f (x) * g (x) = (x-1) * (2x-3)
 f (x) * g (x) = 2x ^ 2 - 3x - 2x + 3
 f (x) * g (x) = 2x ^ 2 - 5x + 3

 For the quotient we have:
 
f (x) / g (x) = (x-1) / (2x-3)
5 0
3 years ago
Chaz is constructing the circumscribed circle for △JKL .
Otrada [13]
In order to construct a circle circumscribed to a triangle, you need to:
- first, find the perpendicular bisector of two of the sides of the triangle; 
- the two perpendicular bisectors will intersect in a point (C) that will be the center of the circle;
- point the compass in C and open it to the width of one of the points of the triangle (CJ or CK or CL);
- draw the circle.

Hence, the correct answer is: D) <span>Construct the perpendicular bisector of JL.</span>
4 0
3 years ago
Camille's skis are 1 1/2 meters long. how many centimeters is this?
Elza [17]
150 centimeters is equal to 1 1/2 meters
5 0
4 years ago
Read 2 more answers
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