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viktelen [127]
2 years ago
9

Solve for x. 4x-4<8 AND 9x+5>23

Mathematics
2 answers:
pogonyaev2 years ago
6 0

4x-4<8

Add 4 on both sides

4x<12

Divide 4 on both sides

x<3

9x+5>23

Subtract 5 on both sides

9x>18

Divide 9 on both sides

x>2

*for reference, I will go ahead and add in that x will be greater than 2 and less than 3

2<x<3

Hope I helped!!

Anna007 [38]2 years ago
4 0

Answer:

2 < x < 3

Step-by-step explanation:

  • 4x - 4 < 8
  • 9x + 5 > 23

Solve for x in the first equation. Add 4 to both sides.

4x < 12

Divide both sides by 4.

x < 3

Solve for x in the second equation. Subtract 5 from both sides.

9x > 18

Divide both sides by 8.

x > 2

We know that x is greater than 2 but less than 3, therefore:

2 < x < 3

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7 0
2 years ago
Please please help!!!! According to the probability distribution below, what is the expected value of X? X 0 1 2 3 4 5 P(X) 0.3
Novay_Z [31]

Answer:

D.) The expected value is 1.78

Step-by-step explanation:

The expected value of a probability distribution is evaluated using the formula.

Expected Value, E(X)=\sum^{n}_{i=1}x_iP(x_i)

Therefore, from the given probability distribution, we have:

E(X)=(0*0.3)+(1*0.2)+(2*0.16)+(3*0.2)+(4*0.04)+(5*0.1)

E(X)=1.78

The Expected value of X is 1.78.

The correct option is D.

4 0
3 years ago
Evaluate this expression. 5^-3
sweet-ann [11.9K]

Answer:

\Huge \boxed{\frac{1}{125}}

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

\displaystyle \frac{1}{5^3}

\displaystyle 5^3=5\times5\times5=125

\displaystyle \frac{1}{125}=125

\large \boxed{\frac{1}{125}}, which is our answer.

Hope this helps!

4 0
3 years ago
4x-10=30<br> 2n-7=30 <br> S/3+2=4
emmasim [6.3K]

Answer:

x=10 n=18.5 s=6

Step-by-step explanation:

4x-10=30

Add 10 to both sides

4x-10+10=30+10

4x=40

Divide by 4 on both sides

(4x)/4=40/4

x=10

2n-7=30

Add 7 to both sides

2n-7+7=30+7

2n=37

Divide by 2 on both sides

(2n)/2=37/2

n=18.5

(s/3)+2=4

Subtract 2 from both sides

(s/3)+2-2=4-2

(s/3)=2

Multiply by 3 on both sides

3s/3=2*3

s=6

6 0
3 years ago
1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into
iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

D=1500-1466=34

6 0
3 years ago
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