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Maurinko [17]
3 years ago
9

How many grams are in 7 kilometers

Mathematics
2 answers:
Kaylis [27]3 years ago
8 0

Answer:

7000 g

Step-by-step explanation:

olganol [36]3 years ago
8 0

Answer:

7000 g

Step-by-step explanation:

I'm assuming you meant kilograms?

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The Wall Street Journal reported that Walmart Stores Inc. is planning to lay off 2300 employees at its Sam's Club warehouse unit
Advocard [28]

Answer:

(a) The mean is 52 and the median is 55.

(b) The first quartile is 44 and the third quartile is 60.

(c) The value of range is 33 and the inter-quartile range is 16.

(d) The variance is 100.143 and the standard deviation is 10.01.

(e) There are no outliers in the data set.

(f) Yes

Step-by-step explanation:

The data provided is:

S = {55, 56, 44, 43, 44, 56, 60, 62, 57, 45, 36, 38, 50, 69, 65}

(a)

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum x\\=\frac{1}{15}[55+ 56+ 44+ 43+ 44+ 56+ 60+ 62+ 57+ 45 +36 +38 +50 +69+ 65]\\=\frac{780}{15}\\=52

Thus, the mean is 52.

The median for odd set of values is the computed using the formula:

Median=(\frac{n+1}{2})^{th}\ obs.

Arrange the data set in ascending order as follows:

36, 38, 43, 44, 44, 45, 50, 55, 56, 56, 57, 60, 62, 65, 69

There are 15 values in the set.

Compute the median value as follows:

Median=(\frac{15+1}{2})^{th}\ obs.=(\frac{16}{2})^{th}\ obs.=8^{th}\ observation

The 8th observation is, 55.

Thus, the median is 55.

(b)

The first quartile is the middle value of the upper-half of the data set.

The upper-half of the data set is:

36, 38, 43, 44, 44, 45, 50

The middle value of the data set is 44.

Thus, the first quartile is 44.

The third quartile is the middle value of the lower-half of the data set.

The upper-half of the data set is:

56, 56, 57, 60, 62, 65, 69

The middle value of the data set is 60.

Thus, the third quartile is 60.

(c)

The range of a data set is the difference between the maximum and minimum value.

Maximum = 69

Minimum = 36

Compute the value of Range as follows:

Range =Maximum-Minimum\\=69-36\\=33

Thus, the value of range is 33.

The inter-quartile range is the difference between the first and third quartile value.

Compute the value of IQR as follows:

IQR=Q_{3}-Q_{1}\\=60-44\\=16

Thus, the inter-quartile range is 16.

(d)

Compute the variance of the data set as follows:

s^{2}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{15-1}[(55-52)^{2}+(56-52)^{2}+...+(65-52)^{2}]\\=100.143

Thus, the variance is 100.143.

Compute the value of standard deviation as follows:

s=\sqrt{s^{2}}=\sqrt{100.143}=10.01

Thus, the standard deviation is 10.01.

(e)

An outlier is a data value that is different from the remaining values.

An outlier is a value that lies below 1.5 IQR of the first quartile or above 1.5 IQR of the third quartile.

Compute the value of Q₁ - 1.5 IQR as follows:

Q_{1}-1.5QR=44-1.5\times 16=20

Compute the value of Q₃ + 1.5 IQR as follows:

Q_{3}+1.5QR=60-1.5\times 16=80

The minimum value is 36 and the maximum is 69.

None of the values is less than 20 or more than 80.

Thus, there are no outliers in the data set.

(f)

Yes, the data provided indicates that the Walmart is meeting its goal for reducing the number of hourly employees

6 0
3 years ago
The floor and ceiling of a room represent planes that are _____
kicyunya [14]
They are parallel planes  
4 0
3 years ago
What is the radius of a cylinder with a height of 5 inches and volume of 62.8in^3 ?
never [62]
Square root 62.8. Which will give you 7.9.
7.9 divided by pi times 5.
7.9 divided by 15.7.
The radius would be 1.9 if left as a decimal, but rounded to the whole number would be 2.
Hope this helps and answers your problem!!!
6 0
3 years ago
The combined area of two squares is 45 square centimeters.each side of one square is twice as long as the side of the other .wha
serg [7]
Formula of square area
a = s²
thus, area of the first square could be written as s₁² and area of the second square could be written as s₂²

First, write an expression in the form of equation system
An expression for "The combined area of two squares is 45 square centimeters" is:
⇒ s₁² + s₂² = 45 <em>(first equation)</em>
An expression for "Each side of one square is twice as long as side of the other" is:
⇒ s₁ = 2s₂ <em>(second equation)</em>

Second, solve the equation system by substitution method.
⇒ We could substitute 2s₂ to s₁ (second equation) in the first equation in order to find the value of s₂
s₁² + s₂² = 45
(2s₂)² + s₂² = 45
(2²)(s₂)² + s₂² = 45
4s₂² + s₂² = 45
5s₂² = 45
s₂² = 45/5
s₂² = 9
s₂² = 3²
s₂ = 3

⇒ Substitute the value of s₂ to the second equation in order to find the value of s₁
s₁ = 2s₂
s₁ = 2(3)
s₁ = 6

The length of each side of the larger square is 6 centimeters
3 0
4 years ago
What are the solutions to the quadratic equation 4x2 = 64?
Karolina [17]
<h2>Greetings!</h2>

Answer:

x = −4 and x = 4

Step-by-step explanation:

4x² = 64

Lets get x² on its own. To do this we divide each sides by 4:

x² = 16

Now to get just x, we need to square root this answer:

√x² = √16

x = √16

x = 4

But this can be ±4 as it -4 and 4 squared both give 16.

So your answer is x = −4 and x = 4


<h2>Hope this helps!</h2>
7 0
3 years ago
Read 2 more answers
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