(a) The "average value" of a function over an interval [a,b] is defined to be
(1/(b-a)) times the integral of f from the limits x= a to x = b.
Now S = 200(5 - 9/(2+t))
The average value of S during the first year (from t = 0 months to t = 12 months) is then:
(1/12) times the integral of 200(5 - 9/(2+t)) from t = 0 to t = 12
or 200/12 times the integral of (5 - 9/(2+t)) from t= 0 to t = 12
This equals 200/12 * (5t -9ln(2+t))
Evaluating this with the limits t= 0 to t = 12 gives:
708.113 units., which is the average value of S(t) during the first year.
(b). We need to find S'(t), and then equate this with the average value.
Now S'(t) = 1800/(t+2)^2
So you're left with solving 1800/(t+2)^2 = 708.113
<span>I'll leave that to you</span>
To isolate the variable q, divide both sides by 3:
q3 ÷ 3 = 64 ÷ 3
q = 21.33 or 21 1/3
If the q is cubed(I can't really tell), however, you would use the cube root:
³√q³ = ³√64
q = 4
4/6=2/3 (divide both numerator and denominator by 2 (gcd)).
Hope this helps.
Answer:
51.3
Step-by-step explanation:
12 meters is equal to 39.3701 feet.
1 meter is equal to 3.28084 feet.
