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3 years ago

6. What will you get when you combine -14, -9 and 3 A. 12 B. 58 C.-12 D. -58

Mathematics

2 answers:

icang [17]3 years ago

8 0

Answer:

When you combine -14 -9and3

than you actually get -20

vlada-n [284]3 years ago

4 0

Answer:

the answer is A I think it will help u

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The simplified form of R(x) is $R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}$

<h3>Simplifying an expression </h3>

From the question, we are to simplify the expression

From the given information,

$f(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30}$

and

$g(x) =\frac{x^{2}-9x+20 }{x^{2}-12x+36}$

Also,

$R(x) = f(x) \div g(x)$

∴ $R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \div \frac{x^{2}-9x+20 }{x^{2}-12x+36}$

$R(x) =\frac{x^{2}-11x+28 }{x^{2}-11x+30} \times \frac{x^{2}-12x+36 }{x^{2}-9x+20}$

Factoring each of the quadratics

$R(x) =\frac{x^{2}-7x-4x+28 }{x^{2}-6x-5x+30} \times \frac{x^{2}-6x-6x+36 }{x^{2}-4x-5x+20}$

$R(x) =\frac{x(x-7)-4(x-7) }{x(x-6)-5(x-6)} \times \frac{x(x-6)-6(x-6) }{x(x-4)-5(x-4)}$

$R(x) =\frac{(x-4)(x-7)}{(x-5)(x-6)} \times \frac{(x-6)(x-6)}{(x-5)(x-4)}$

Simplifying

$R(x) =\frac{(x-7)}{(x-5)} \times \frac{(x-6)}{(x-5)}$

$R(x) =\frac{(x-7)(x-6)}{(x-5)(x-5)}$

$R(x) =\frac{x^{2} -6x-7x+42}{x^{2} -5x-5x+25}$

$R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}$

Hence, the simplified form of R(x) is $R(x) =\frac{x^{2} -13x+42}{x^{2} -10x+25}$

Learn more on Simplifying an expression here: brainly.com/question/1280754

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6. What will you get when you combine -14, -9 and 3 A. 12 B. 58 C.-12 D. -58​

6. What will you get when you combine -14, -9 and 3 A. 12 B. 58 C.-12 D. -58