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ad-work [718]
3 years ago
6

Theo has one piece of train track that is 74 millimeters long and a second piece of train track that is 97 millimeters long.

Mathematics
2 answers:
ziro4ka [17]3 years ago
8 0

Answer:

171 m i hop this helps

Step-by-step explanation:

Lana71 [14]3 years ago
7 0
Theo has 171 m of track.
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Which estimation could be used to make sure the answer is reasonable?
Naddika [18.5K]

Let's go through each answer.

A.

Answer: The amount left over was 4.05 L.

Estimation: 3.15 + 4.75 is about 7.

7 L – 4 L = 3 L

The amount left over was about 3 L.

This is incorrect because 3.15+4.75 is closer to 8 than 7.

B.

Answer: The amount left over was 3.95 L.

Estimation: 3.15 + 4.75 is about 8.

8 L – 4 L = 4 L

The amount left over was a little less than 4 L.

This is correct because 3.15+4.75 is close to 8 and to find the amount left over you do have to subtract.

The correct answer is B.

Answer: The amount left over was 3.95 L.

Estimation: 3.15 + 4.75 is about 8.

8 L – 4 L = 4 L

The amount left over was a little less than 4 L.

Hope this helps!. If it helped, please rate, thank, and if it really helped, give brainliest. It helps me rank up. Thanks! :)

3 0
3 years ago
What is the actual slope of a line with the points (-4, 9) and (3, -5)?
Vikentia [17]

Answer:

slope=∆y/∆x=9+5/-4-3=14/-7=-2

6 0
2 years ago
Read 2 more answers
How do i determine the domain and the equation of the vertical asymptote of the equation f(x)=ln (x+2)-1?
svetlana [45]
If I am reading the equation correctly, I do not believe it has a solution. 
3 0
3 years ago
The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is f(x)=0.0
uysha [10]

Answer:

a) 20%

b) 40%

c) Mean = 62.5 seconds; Variance = 52.083 seconds

Step-by-step explanation:

The time it takes a hematology cell counter to complete a test on a blood sample is continuously distributed over the period of 50 to 75 seconds with probability f(x) = 0.04.

a) The percentage of tests require more than 70 seconds is:

P(X>70) = 1- \frac{70-50}{75-50} \\P(X>70) =0.2 = 20\%

b)The percentage of tests that require less than one minute (60 seconds) is:

P(X70) =0.4 = 40\%

c) The mean and variance of a continuous distribution are determined by:

M=\frac{A+B}{2}=\frac{50+75}{2}\\ M= 62.5\ seconds\\\\V=\frac{(B-A)^2}{12}=\frac{(75-50)^2}{12}\\  V= 52.083\ seconds

Mean = 62.5 seconds.

Variance = 52.083 seconds.

3 0
3 years ago
Find the missing side or angle.
Makovka662 [10]
360-142 and you get ur answer unless it’s not a 360 degree
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2 years ago
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