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2 years ago

If events X and Y are independent, what must be true? Check all that apply.

Mathematics

1 answer:

siniylev [52]2 years ago

3 0

Answer:

Step-by-step explanation:

I think this was cut off, the options aren't full.

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What's the slope and speed of plane A and B

deff fn [24]

The slope and speed of Plane A is 375mph and slope and speed for Plane B is 425 mph... so Plane A travels the fastest

6 0

2 years ago

the taco truck sells tacos for $3 and burritos for $4. the number of items sold on a tuesday is 125 with a total income of $430.

butalik [34]

Answer:

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

3 T + 4 B =425

T + B = 125

Where T is the number of tacos sold, and B is the number of burritos sold.

Multiplying the second equation by 3, and subtracting it to the first equation:

3 T + 4 B =425

3T + 3B = 375

___________

B =50

Replacing B in any equation:

T + B = 125

T +50 =125

T =125-50

T = 75

Feel free to ask for more if needed or if you did not understand something.

5 0

2 years ago

The reaction time (in seconds) to a certain stimulus is a continuous random variable with pdf f(x) 5 5 3 2 ? 1 x2 1

muminat

The probability that the reaction time for this density function is at most 2.5 seconds is equal to 0.9.

<h3>What is a density function?</h3>

A density function can be defined as a type of function which is used to represent the density of a continuous random variable that lies within a specific range.

<h3>How to calculate the probability that reaction time is at most 2.5 seconds?</h3>

P(X ≤ 2.5) = Fx(2.5)

Fx(2.5) = 3/2 - 3/2(2.5)

Fx(2.5) = 3/2 - 3/5

Fx(2.5) = 0.9.

Read more on density function here: brainly.com/question/14448717

#SPJ4

Complete Question:

The reaction time (in seconds) to a certain stimulus is a continuous random variable with pdf:

f(x) = $\left \{ {{\frac{3}{2x^2} \;1 \leq x\leq 3} \atop {0}\;otherwise} \right$

What is the probability that reaction time is at most 2.5 seconds?

7 0

1 year ago

I will mark brainiest is my answer is correct?

Alex Ar [27]

Your answer is correct

5 0

2 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago