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3 years ago

The highest point over the entire domain of a function or relation

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

Answer:

The highest point over the entire domain of a function or relation is called an absolute maximum.

Step-by-step explanation:

For a continuous function f(x) in a closed interval, there exists a value of f(x) that is the highest and that point is called the absolute maximum. The maximum value can be found a number of ways including a graphical method and using the first and second derivative.

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Who has the greater slope?

Levart [38]

Answer:

They both have the same answer.

Step-by-step explanation:

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3 years ago

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NEED HELP ASAP! Question in the photo.

Sonja [21]

Answer:

SAS Postulate

Step-by-step explanation:

You can use the SAS (side, angle, side) postulate that says "if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent"

Side AB is proportionate to DE and

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I hope this helps.

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3 years ago

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poizon [28]

Answer:

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Step-by-step explanation:

f(b)-f(a)/b-a

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6 0

3 years ago

2x 2 (9x 2 −16)

xz_007 [3.2K]

Is the equation2x2(9x+2-16) if so you would do -16+2 first which is -14

Then multiply 2x2 equals 4

4(9x-14)

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You get 36x-56

7 0

3 years ago

Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3

aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= X[bar] - μ ~ $t_{n-1}$

S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= 3690 - 3300 = 2.549

530/√12

The rejection region for this test is two-tailed, with critical values:

$t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201$

$t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201$

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0

3 years ago