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3 years ago

I NEED HELP!!!

Mathematics

2 answers:

Alex777 [14]3 years ago

5 0

Answer:

nechfejbjrenrv

Step-by-step explanation:

y u asking usss no maam ;)

kari74 [83]3 years ago

4 0

A positive relationship. The reason being y=3x represents the overall slope of the equation, as well as the point (3,9) and (5,15) are the outcomes of the equation. For instance when you start at the origin with the equation you move up 3 and move to the right 1 this is the same with (3,9) and (5,15) just continuing the pattern with these points.
(e.g: (1,3), (2,6), (3,9), (4,12), (5,15).)

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Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

4 years ago

A rental car company charges $30 a day plus $0.05 a mile. Which expression could be used to find the cost of renting a car for m

Gnoma [55]

Answer:

Step-by-step explanation:

Since the company earns $0.05 for every mile, we would multiply m by 0.05. We also add it with 30 since it is a base charge. This makes it C

It can't be A or B since that would mean the company earns $30.05 for every mile.

It can't be D since that would mean the company earns $30 for every mile with a base charge of $0.05.

6 0

3 years ago

Nas funções f(x) = -3x+9; f(x) = 2x-4 e f(x) = 5x-5, caso construamos seus respectivos gráficos, informe respectivamente os pare

Likurg_2 [28]

1st option

{(3,0) e (0,9)}; {(2,0) e (0,-4)}; {(1,0) e (0,-5)}

see screenshot

sorry btw, no hablo espanol

8 0

3 years ago

Its pretty easy if you are good at math! Please help!

aleksley [76]

Step-by-step explanation:

Explanation:

The trick is to know about the basic idea of sequences and series and also knowing how i cycles.

The powers of i will result in either: i, −1, −i, or 1.

We can regroup i+i2+i3+⋯+i258+i259 into these categories.

We know that i=i5=i9 and so on. The same goes for the other powers of i.

So:

i+i2+i3+⋯+i258+i259

=(i+i5+⋯+i257)+(i2+i6+⋯+i258)+(i3+i7+⋯+i259)+(i4+i8+⋯+i256)

We know that within each of these groups, every term is the same, so we are just counting how much of these are repeating.

=65(i)+65(i2)+65(i3)+64(i4)

From here on out, it's pretty simple. You just evaluate the expression:

=65(i)+65(−1)+65(−i)+64(1)

=65i−65−65i+64

=−65+64

=−1

So,

i+i2+i3+⋯+i258+i259=-1

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3 years ago

Select the three inequalities that have n = 3 in the solution set

SCORPION-xisa [38]

Answer:

Its just E

I'm sorry if I'm wrong

4 0

3 years ago

Read 2 more answers