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vagabundo [1.1K]
3 years ago
11

Prove that cos(2????) = 2cos2(????) − 1 for any real number ????.

Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

Sure

Step-by-step explanation:

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(1 point) If p(x) and (x) are arbitrary polynomials of degree at most 2, then the mapping =p(-1)q(-1) + p(070) +p(3)q(3) defines
Ainat [17]

If p(x) and q(x) are arbitrary polynomials of degree at most 2 then

||p||||q|| = 26(\sqrt{640}) and angle between p(x) and q(x) is 0.233.

Given that

<p,q> = p(-1)q(-1) + p(0) q(0) + p(3)q(3)

and p(x) = 2x²+ 6 , q(x)= 4x²-4x

then the values of p and q at x = -1,0,3 are given as;

x = -1,

p(-1) = 2(-1)² + 6 = 8   ,    q(-1) = 4(-1)² - 4(-1) = 8

x = 0,

p(0) = 2(0)² + 6 = 6   ,    q(0) = 4(0)² - 4(0) = 0

x = 3,

p(3) = 2(3)² + 6 = 24  ,  q(3) = 4(3)²- 4(3) = 24.

<p,q> = p(-1)q(-1) + p(0)q(0) + p(3)q(3)

         = (8)(8) + (6)(0) + 24(24)

         = 64 + 0 + 576

<p,q> = 640

Now we have to find ||p|| ||q||, for this we'll find ||p|| and ||q||

||p|| = \sqrt{ < p,p > }

     = \sqrt{8(8) + 6(6) + 24(24)}

     = \sqrt{676}

||p|| = 26

and

||q|| = \sqrt{ < q,q > }

      =\sqrt{8(8) + 0(0) + 24(24)}

||q||  =\sqrt{640}

∴||p||||q|| = 26(\sqrt{640\\)

Now we have to find angle between p(x) and q(x),

∴ α = cos⁻¹\frac{ < p,q > }{||p||||q||}

      = cos ⁻¹ \frac{640}{26(\sqrt{640}) }

      = cos ⁻¹ \frac{4\sqrt{10} }{13}

  α  = 13.34°

In radian

α = 0.233.

To know more about Inner product here

brainly.com/question/14185022

#SPJ4

5 0
1 year ago
10-3v-1)=5(9-v) solve for v please show work
Aleksandr [31]

Answer:

v=18

Step-by-step explanation:

10-3v-1=5(9-v)

first open the bracket

10-3v-1=45-5v

5v-3v=45-9

2v=36

v=18

7 0
3 years ago
PLEASE ANSWER FAST WILL DO BRAINLIESTThe coordinate grid shows points A through K. What point is a solution to the system of ine
Alja [10]

Answer:  points B (4,7) and  I (9,3)

If the inequalities are

y > −2x + 10  and y> (½)x -2

Step-by-step explanation:  If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant  y > 1/(2x-2) for the second inequality. If so, we start over!

You can test the values for all the points, but it appears that (4,7) and (9,3) both work.

The other coordinates appear to be outside the solution -- the dark-shaded area.

I hope this is your Brainliest answer. It was a lot of work!

4 0
3 years ago
What is 2 wholes minus 1/4
bonufazy [111]
2-1/4
2/1=8/4       Multiply top and bottom by 4
8/4-1/4
7/4
1 3/4
3 0
4 years ago
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Can someone help me with this math question? The answer is suppose to be
Tanzania [10]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

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3 0
4 years ago
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