All categories

4 years ago

I'll give u premium snap

Mathematics

1 answer:

Vinil7 [7]4 years ago

3 0

Answer:

A and D

Step-by-step explanation:

You might be interested in

Write a polynomial if least degree with roots 9 and -6

klio [65]

Answer:

x² -3x - 54

Step-by-step explanation:

given roots of a polynomial are 9 and -6

this means that (x-9) and (x+6) are factors of the polynomial.

To get the polynomial with the least degree, simply multiply the two factors to obtain a quadratic expression (degree 2)

(x-9) (x+6)

= x² + 6x -9x -54

= x² -3x - 54

8 0

3 years ago

How to order 1/5, 1.35,-0.2 from least to greatest

Alik [6]

Answer:

-0.2, 1/5, 1.35

Step-by-step explanation:

-0.2 is the only negative, therefore it has the least value

1/5 can be shown as 0.5 which is less than 1.35

7 0

3 years ago

The concentration of hexane (a common solvent) was measured in units of micrograms per liter for a simple random sample of sixte

goldenfox [79]

Answer:

Yes, it can be concluded that the mean hexane concentration is less in treated water than in unsaturated water

Step-by-step explanation:

The number of of specimen in the samples of untreated water, n₁ = 16

The sample mean, $\overline x_1$ = 228.0

The sample standard deviation, s₁ = 4.3

The number of of specimen in the samples of treated water, n₂ = 20

The sample mean, $\overline x_2$ = 224.6

The sample standard deviation, s₂ = 5.0

The level of significance = 0.10

The null hypothesis, H₀; $\overline x_1$ ≥ $\overline x_2$

The alternative hypothesis, Hₐ; $\overline x_1$ < $\overline x_2$

The degrees of freedom = 16 - 1 = 15

The test statistic, $t_{\alpha}$ = 1.341

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

Plugging in the values, we get;

$t=\dfrac{(224.6- 228.0)}{\sqrt{\dfrac{5.0^{2}}{20} -\dfrac{4.3^{2} }{16}}} \approx -11.0675$

Given that the t-value is large, the corresponding p-value is low, therefore, we fail to reject the null hypothesis and there is considerable statistical evidence to suggest that the mean hexane concentration is less in treated than in untreated water, therefore, we have; $\overline x_1$ ≥ $\overline x_2$

6 0

3 years ago

What is the value for x,the length of side bc?7 to

kifflom [539]

Answer:

x = 17.5

Step-by-step explanation:

$\triangle ABC \sim \triangle DEF... (given)$