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3 years ago

Write an equation for the line contains each pair of points. (0, -6), (-3, 3)

Mathematics

1 answer:

IrinaVladis [17]3 years ago

8 0

it's linear line bro

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A movie theater has a seating capacity of 387. The theater charges $5.00 for children, $7.00 for students, and $12.00 of

Rainbow [258]

Answer:

The attendance was 198 children, 90 students and 99 adults.

Step-by-step explanation:

We define:

c: children attendance

s: students attendance

a: adult attendance

The equation that describes the total ticket sales is:

$5c+7s+12a=2808$

We also know that the children attendance doubles the adult attendance:

$c=2a$

The third equation is the seating capacity, which we assume is full:

$c+s+a=387$

We start by replacing variables in two of the equations:

$c=2a\\\\s=387-c-a=387-2a-a=387-3a$

Then, we solve the remaining equation for a:

$5c+7s+12a=2808\\\\5(2a)+7(387-3a)+12a=2808\\\\10a+(2709-21a)+12a=2808\\\\10a+12a-21a=2808-2709\\\\a=99$

Then, we solve for the other two equations:

$c=2a=2*99=198\\\\s=387-3a=387-3*99=387-297=90$

The attendance was 198 children, 90 students and 99 adults.

8 0

3 years ago

Two less than 3/2 of a number (x) is more than 5 1/2

djverab [1.8K]

<h2>Answer: (3/2)x - 2</h2>

Step-by-step explanation:

Let the number be x.

"Two less than 3/2 of a number (x)" means (3/2)x - 2

"is no more than" means "≤"

5 1/2

* Hopefully this helps:) Mark me the brainliest:)!!!

4 0

3 years ago

Write the point-slope form of the equation of the line that passes through the point (1, 3) and has a slope of 2. include your w

zubka84 [21]

We must plug into point-slope form.
Formula for point-slope: $y-y1=m(x-x1)$
Plug in the values: $y-3 = 2(x-1)$

And there you have your answer in point-slope form

8 0

3 years ago

Math problem 6 divided by 10/12

Darina [25.2K]

The answer to your problem would be 0.05

3 0

3 years ago

Read 2 more answers

Please help me, WORST TEACHERR!

notsponge [240]

Answer:

b. The supplements of congruent angles are congruent

Explanation:

Note that $\angle TKL$ is a supplement of $\angle 3$ and $\angle TLK$ is a supplement of $\angle 4$ .

Since $\angle 3 \cong \angle 4$ , $\angle TKL \cong \angle TLK$ because the supplement of the congruent angles are congruent.

8 0

3 years ago