9514 1404 393
Answer:
300 g
Step-by-step explanation:
The problem statement tells us ...
36g = 0.12×d . . . . . where d represents the daily value
36g/0.12 = d = 300g . . . . divide by the coefficient of d
300 g of carbohydrates per day are recommended.
The answer is blank is greater than five or —>5
Answer:
<h2>
min: 52</h2><h2>
max: 78</h2><h2>
median: 63</h2><h2>
lower quartile median: 54</h2><h2>
upper quartile median: 73</h2><h2>
interquartile range: 19</h2>
Step-by-step explanation:
the temperatures ordered from least to greatest
52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78
the min is 52
the max is 78
median:
52, 53, 54, 54, 57, 62, 64, 69, 73, 73, 77, 78
(62+64)/2=126/2=63
thus the median is 63
now we don't include the median in finding the upper and lower quartile medians:
lower quartile median:
52, 53, 54, 54, 57, 62
54 (same #s no need to add up and divide by 2)
upper quartile median:
64, 69, 73, 73, 77, 78
73 (same #s no need to add up and divide by 2)
interquartile range is:
upper quartile median-lower quartile median:
73-54
19
Answer:
Total Weight of all the five boys is <em>234 kg</em>.
Step-by-step explanation:
Given that there are <em>five </em>boys.
They have weighed themselves in pairs in all possible combinations.
And their weights are: 88 kg, 90 kg, 91 kg, 92 kg, 93 kg, 94 kg, 95 kg, 96 kg, 98 kg and 99 kg
To find: Total weights of the five boys = ?
Solution:
First of all, we need to find the total number of pairs that can be formed from a total of 5 number of boys.
Total number of pairs possible =
If we select one boy, there are 4 other boys with whom pairs can be formed.
So, every boy's weight is repeated 4 number of times in these 10 pairs.
If we add all the 10 measured weights given and then divide them with 4 we will get the total weight of the five boys.
So, Total Weight of all the five boys is <em>234 kg</em>.