Answer:
y=5sin(16pix)+3
Step-by-step explanation:
Amp=5 means our curve is either y=5sin(bx+c)+d or y=-5sin(bx+c)+d.
y=sin(x) has period 2pi.
So y=sin(bx) has period 2pi/b.
We want 2pi/b=1/8.
Cross multiplying gives: 16pi=b
y=5sin(16pix+c)+d
d=3 since we want midline y=3.
y=5sin(16pix+c)+3
We can choose c=0 since we aren't required to have a certain phase shift.
y=5sin(16pix)+3
We are given the following quadratic equation

The vertex is the maximum/minimum point of the quadratic equation.
The x-coordinate of the vertex is given by

Comparing the given equation with the general form of the quadratic equation, the coefficients are
a = 2
b = 7
c = -10

The y-coordinate of the vertex is given by

This means that we have a minimum point.
Therefore, the minimum point of the given quadratic equation is
5.8927 x 10^4
it easy it must be a number between 1-10 (this time 5.8927) and then the 10^4 its because the decimal point moves 4 spaces
Answer:
Step-by-step explanation:
The equation is y = -4x²
Next time, please share the answer choices.
Here's a short table of possible solutions:
x -x² (x, y)
----- ------ ---------
0 0 (0, 0)
2 -4 (2, -4)
-3 -9 (-3, -9)
Answer:
The correct option is;
An isosceles trapezoid with legs of length 8
Step-by-step explanation:
The correct option is an isosceles trapezoid with legs of length 8
The given properties of the quadrilateral are;
1) One pair of equal opposite sides
2) One pair of parallel opposite sides
From the given options, the two options which are not parallelograms are the kite and the trapezoid
However given that the option of the kite has a pair of adjacent side of length 8, with the given pair of equal length opposite side of length 8, we have that all the sides of the quadrilateral will be of length 8, and the figure cannot be a kite
An isosceles trapezoid of leg length 8 has one pair of equal length opposite sides of length 8 and one pair of parallel sides of unequal length
Given that the length of the lines that make up the pair of opposite parallel sides in the figure are not specified, the figure can be described by as being an isosceles trapezoid.