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babymother [125]
3 years ago
11

What is PA Enter your answer in the box

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

3

Step-by-step explanation:

P is the in-center

⇒PA=PE=PD because they are in-radius of the in-circle

We know that, tangent segments drawn from a point outside the circle are always equal in length

⇒DK=EK=7.2

In right triangle PKE,

using Pythagoras' Theorem : PK^{2}=PE^{2}+KE^{2}

⇒PE^{2}=PK^{2}-KE^{2}

⇒PE=\sqrt{PK^{2}-KE^{2} }

⇒PE^{2}=\sqrt{7.8^{2}-7.2^{2}} }

⇒PE=3

Therefore, PA=3

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A door of a lecture hall is in a parabolic shape. The door is 56 inches across at the bottom of the door and parallel to the flo
Arada [10]

Answer:

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. (See attachment included below). Head must 15.652 inches away from the edge of the door.

Step-by-step explanation:

A parabola is represented by the following mathematical expression:

y - k = C \cdot (x-h)^{2}

Where:

h - Horizontal component of the vertix, measured in inches.

k - Vertical component of the vertix, measured in inches.

C - Parabola constant, dimensionless. (Where vertix is an absolute maximum when C < 0 or an absolute minimum when C > 0)

For the design of the door, the parabola must have an absolute maximum and x-intercepts must exist. The following information is required after considering symmetry:

V (x,y) = (0, 32) (Vertix)

A (x, y) = (-28, 0) (x-Intercept)

B (x,y) = (28. 0) (x-Intercept)

The following equation are constructed from the definition of a parabola:

0-32 = C \cdot (28 - 0)^{2}

-32 = 784\cdot C

C = -\frac{2}{49}

The parabolic shape of the door is represented by y - 32 = -\frac{2}{49}\cdot x^{2}. Now, the representation of the equation is included below as attachment.

At x = 0 inches and y = 22 inches, the distance from the edge of the door that head must observed to avoid being hit is:

y -32 = -\frac{2}{49} \cdot x^{2}

x^{2} = -\frac{49}{2}\cdot (y-32)

x = \sqrt{-\frac{49}{2}\cdot (y-32) }

If y = 22 inches, then x is:

x = \sqrt{-\frac{49}{2}\cdot (22-32)}

x = \pm 7\sqrt{5}\,in

x \approx \pm 15.652\,in

Head must 15.652 inches away from the edge of the door.

8 0
3 years ago
Given QR || TU. Enter segments in the blanks provided that would result in a true<br> equation.
vichka [17]

The similar Triangle OPN and triangle LMN are similar have the ratio LM / MN = OP / NP

<h3>What are similar figures?</h3>

Two figures are said to be similar if they have the same shape and the ratio of their corresponding sides are in the same proportion.

Triangle OPN and triangle LMN are similar, hence:

LM / MN = OP / NP

The similar Triangle OPN and triangle LMN are similar have the ratio LM / MN = OP / NP

Find out more on similar figures at: brainly.com/question/2644832

5 0
2 years ago
Janae bought a new house. The house is quite large, 2500 square feet, and has a nice sized backyard. She bought the house on a f
Bond [772]

Solution :

Rephrasing is defined as to rewriting or expressing the idea or the content in an alternative way.

So rephrasing the question, we get :

Janae bought a new big size house of 2500 square feet with a large size backyard at $ 129,900. Janae wants fence her backyard so that her dog, Lyle can play on the backyard. Before fencing she wants to know the perimeter of the fencing or the size of the yard so that she could fence it. The measures of her yard is :

length : (x-7)

width : (x+2)

4 0
3 years ago
4. So
Serhud [2]

Answer:

P=29.95+0.05m+2.95

Step-by-step explanation:

The monthly plan costs starts at $29.95, so we're not changing that.

For each monthly plan, we have to pay a tax of $2.95, so we're not changing that.

If we go over 1,000 minutes, we have to pay $0.05 for every minute we go over, and with the fact that m represents each minute over 1,000, we're going to have to represent minutes over 1,000 as 0.05m in our equation.

Set up your equation:

P=29.95+0.05m+2.95

6 0
3 years ago
Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t
noname [10]

Answer:

a.y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

by(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

Step-by-step explanation:

1.y''-4y'+4y=6x e^{2x}

Auxillary equation

D^2-4D+ 4=0

(D-2)(D-2)=0

D=2,2

Then complementary solution =C_1e^{2x}+C_2xe^{2x}

Particular solution =\frac{6 xe^{2x}}{(D-2)^2}

D is replace by D+2 then we get

P.I=\frac{6xe^{2x}}{0}

P.I=\frac{e^{ax}}{D+a} \cdot .V

where V is a function of x

P.I=\frac}x^3e^{2x}

By integrating two times

Hence, the general solution

y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

b.y''+9y=5 cos x-7 sin x

Auxillary equation

D^2+9=0

D=\pm 3i

C.F=c_1 cos 3x+ c_2sin 3x

P.I=\frac{5 cos x-7 sin x}{D^2+9}

P.I=\frac{sin ax}{D^2+bD +C}

Then  D square is replace by -a square

D^2 is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

4 0
3 years ago
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