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Arisa [49]
3 years ago
11

Boris has 12.92 centimeters of yarn. If he wants to make the yarn into pieces that are 0.38 centimeters long, how many pieces ca

n he make?
Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Divide the total amount by the cut length:

12.92 / 0.38 = 34

He can make 34 pieces.

gizmo_the_mogwai [7]3 years ago
8 0

Answer: 34

Step-by-step explanation:

12.92 / 0.38 = 34 pieces

just division my dude

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The perimeter of a playing field for a certain sport is 174 ft. The field is a rectangle, and the length is 45 ft longer than th
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Answer:

21 ft by 66 ft

Step-by-step explanation:

From the question,

P = 2(L+W)............... Equation 1

Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.

If the Length of the Field is 45 ft longer than the width,

L = 45+W............ Equation 2

Substitute Equation 2 into equation 1

P = 2(45+W+W)

P = 90+4W............. Equation 3

Given: P = 174 ft.

Substitute into equation 3

174 = 90+4W

4W = 174-90

4W = 84

W = 84/4

W = 21 ft.

Substituting the value of W into equation 2

L = 45+21

L = 66 ft.

Hence the dimensions of the playing field is 21 ft by 66 ft

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3 years ago
Y=-x+5 <br> x-y=-9 <br> Solve the system?
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Answer:

x=-2 y=7

Step-by-step explanation:

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Arte-miy333 [17]

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identity 4

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Will all slices created by a slicing plane that passes through a sphere be the same size
Snowcat [4.5K]

Answer:

The suggestion proposed considering special cases, so that’s what we’ll do.

One special case we could consider is when x=0. If h=r, then we have a hemisphere. You may have learnt that the surface area of a sphere is 4πr2, so the answer in this case is 2πr2. Likewise, we can consider the most extreme cases: when h=2r, we get an area of 4πr2 (the entire sphere), and when h=0, we get zero area.

So if we do manage to get a general formula, we will be able to check it in these special cases.

Another possible idea when x=0 is to consider what happens when h is very small. In this case, the surface area looks a lot like a circle, but the radius of the circle does not seem particularly easy to work out, so maybe we’ll leave this one for a moment. (There are things we can do to approximate the radius using more advanced techniques, but they are currently beyond us.)

Another thing we could consider is the situation where h is very small. Then the part of the sphere between the planes looks very much like the frustum of a cone, and we know how to find the (surface) area of such a shape – see Cones.

If we recall our answer from that problem, we find the formulae for the surface area

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Here, R is the radius of the base of the frustum, r is the radius of the top, h is the perpendicular height, s is the slant length and θ is the angle the slant makes with the vertical.

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