3 years ago

Help please!!!!!!!!!!!!

1 answer:

7 0

It should be 5>=

Your welcome

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chubhunter [2.5K]

Answer:

$\boxed{\sf \ \ \ f^{-1}(x)=1+\sqrt{x} \ \ \ }$

Step-by-step explanation:

the minimum of f is for x = 1 and f(1)=0

f is decreasing for x<=1 and increasing for x>=1

so the domain is $[1;+\infty[$

$f^{-1}(f(x))=x =f^{-1}((x-1)^2)\\\\f(f^{-1}(x))=x=(f^{-1}(x)-1)^2$

x>=1 so x is positive and we can take the square root

so $f^{-1}(x)=1+\sqrt{x}$

8 0

3 years ago

Anna71 [15]

15% of 60

.15 × 60 = 9

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3 years ago

Novosadov [1.4K]

Answer:I’m doing this right now do u know the answer?

Step-by-step explanation:

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3 years ago

VikaD [51]

The equation is "x=0", because the x intercepts at the x axis with no y-intercept.

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3 years ago

ale4655 [162]

Answer:

1/3

Step-by-step explanation:

first find a common denominator. in this case its 5. now divide both the numerator and denominator by 5 and there you go :)

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3 years ago