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jarptica [38.1K]
3 years ago
5

Can someone Evaluate 2(4-1)^2

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0

Answer:

The answer is 36

Step-by-step explanation:

First solve in parenthesis; 4-1=3

Then multiply that by the 2 to get 6

Then raise that value by the square root of 6^2 = 36

ipn [44]3 years ago
3 0

Hey there!☺

Answer:\boxed{18}

Explanation:

2(4-1)^2

First, do the parenthesis.

(4-1)=3

Now add the exponent to 3.

3^2

Now do the exponent.

3^2=9

Now multiply 9 by the number we have left which is 2.

2*9=18

18 is your answer.

Hope this helps!☺

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Answer:

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4 0
3 years ago
In the number 8.028 does one 8 have a value of 100 times the other 8 ?
nirvana33 [79]

Answer:

No, The 8 in the ones place of the decimal and the 8 in the thousands. Decimals go by variables of 10 if that makes sense

so hopping from the 8 in the ones place it would go 10, 100,1000.

Therefore the statement is false because the value between the eitghts is not 100 its 1000

6 0
3 years ago
Help quickly plsss<br><br><br><br><br> Hsjsjdjjd
I am Lyosha [343]

Answer:

answer is 75

Step-by-step explanation:

6÷8x100=75%

from 58 to 66 its have 6 colums..thats why 6/8

5 0
3 years ago
Expand<br> c(3c - 3)<br> I need help on this
Rudik [331]

\\ \sf\longmapsto c(3c-3)

Apply distributive law

  • a(b-d)=ab-ad

\\ \sf\longmapsto 3c(c)-3(c)

\\ \sf\longmapsto 3c^2-3c

We can still take common

\\ \sf\longmapsto 3c(c-1)

4 0
2 years ago
Read 2 more answers
Please help ASAP IM IN DESPREATE NEED OF HELP
Advocard [28]

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality -y \le -2x-3.  You can make this easier to work with by multiplying through by -1.  Remember to switch the inequality sign when multiplying by a <u>negative</u> number.  OK, you get the inequality

y \ge 2x+3.

The graph will be a half-plane -- all the points on one side of a line.  The line that is the boundary of the half-plane has an equation:  y=2x+3 -- just use an  =  sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form:  y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1).  Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5).  Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality y \ge 2x+3 is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the <u>other</u> side!)

An easy point to pick in this case is the origin, (0, 0).  Put zeros in for x and y in the inequality, and you'll get the statement 0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3.  That's <u>false</u>, so shade the side of the line <u>not</u> containing the origin.  In the image below, the shading is in purple.

All right, now for the other inequality, x+2\le 0.  Subtract 2 from both sides and the inequality becomes x \le -2.  This, too, graphs as a half-plane whose boundary line has equation x=-2.  Graph the line.  A line with an equation that has  x  in it but not  y is a vertical line with all its x-coordinates equal to the number on the right side of the equation.  This line is vertical and goes through points such as (-2, 0).

Pick a point <u>not</u> on the line (the origin works again).  Put the coordinates into the inequality to get 0\le -2 which is <u>false</u>.  Shade the side of the vertical line which does <u>not</u> contain the origin.  In the image below, the shading is in black.

Finally,  YAY!  \o/ ,  the solutions to the system are all the points in the plane that got shaded twice.  In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities x \ge 0 and y \ge 0 in it.  These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis <u>and</u> to the right of the y-axis.

7 0
3 years ago
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