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jarptica [38.1K]
3 years ago
5

Can someone Evaluate 2(4-1)^2

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
5 0

Answer:

The answer is 36

Step-by-step explanation:

First solve in parenthesis; 4-1=3

Then multiply that by the 2 to get 6

Then raise that value by the square root of 6^2 = 36

ipn [44]3 years ago
3 0

Hey there!☺

Answer:\boxed{18}

Explanation:

2(4-1)^2

First, do the parenthesis.

(4-1)=3

Now add the exponent to 3.

3^2

Now do the exponent.

3^2=9

Now multiply 9 by the number we have left which is 2.

2*9=18

18 is your answer.

Hope this helps!☺

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If square ABCD with side length of 7 units is reflected over the line y=x, what is length A'B'?
Art [367]

Answer:

  7

Step-by-step explanation:

Reflection is a rigid transformation, so the side length does not change.

  A'B' = 7

5 0
3 years ago
Abigail jogged 10.6 miles in 2.5 hours. What is her jogging speed in miles per hour? A. 4.32 miles/hour B. 4 miles/hour C. 4.24
Lelechka [254]

do miles/hour =

10.6 miles/2.5 hours =

10.6/2.5 =

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5 0
3 years ago
Read 2 more answers
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
PLEASE HELP ME IM HONESTY SO CONFUSED WITH THE ANSWERS GIVEN
Drupady [299]

Answer:

C. The sum of 18 and half the product of 9 and 4.

8 0
2 years ago
Let F(x,y)=1+sqrt(4-y^2). . (a) Evaluate F(3,1). (b) Find and sketch the domain of F. (c) Find the range of F
charle [14.2K]
The goal of this function is to get  a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2. 
6 0
3 years ago
Read 2 more answers
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