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2 years ago

Can someone please help!!!

Mathematics

1 answer:

Snezhnost [94]2 years ago

6 0

Answer:

I think is the 3rd one but I am not sure

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Choose the missing step in the given solution to the inequality −6x − 10 > 14 + 2x. −6x − 10 > 14 + 2x _______________ −8x

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-6x - 10 > 14 + 2x

-2x -2x

-8x - 10 > 14 THIS IS THE MISSING STEP

+10 +10

-8x > 24

$\frac{-8x}{-8}$ $\frac{24}{-8}$

x < -3

Answer: x < -3

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2 years ago

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3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

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3 years ago

Find thw product of (x+3)(x-3)(x+7)

Lesechka [4]

Answer:

x^3+7x^2−9x−63

Step-by-step explanation:

can i please have brainliest

6 0

2 years ago

PLEASE HELP ME The length of the one of the legs of a right triangle is 8m and the hypotenuse is 12m. Which of the following cho

Bas_tet [7]

Answer:

The length of the other leg is 8.94 m.

Step-by-step explanation:

Given that,

Hypotenuse of a right triangle is 12 m

The length of the one of the legs of a right triangle is 8 m

We need to find the length of the other leg. It is based on the concept of Pythagoras theorem. Let the other leg is h. So, according to this theorem,

$H^2=b^2+h^2$

H = hypotenuse = 12 m

b = base = 8 m

$h^2=H^2-b^2\\\\h^2=12^2-8^2\\\\h=\sqrt{80}\\\\h=8.94\ m$

So, the length of the other leg is 8.94 m.

8 0

2 years ago