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3 years ago

This is my very first trig problem and I'd like to know how to tackle this. Please explain how I can do problems like these in t

he future!

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

$\tan(50°) = \frac{QR}{PQ} \Leftrightarrow QR = PQ \tan(50°) = 8.1 \tan(50°) \approx9.65 \\ \cos(50°) = \frac{PQ}{PR} \Leftrightarrow PR = \frac{PQ}{\cos(50°)} = \frac{8.1}{\cos(50°)} \approx12.6$

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