So the first two questions are asking for points of intercept. a is asking where the function crosses the x, in this case it is where y=0. So your x intercept is at x= 1,5. Then to find the y intercept it is where x=0, so just substitute 0 for x. Then you get your y intercept as y=5. Because your coefficient for the quadratic function is positive your function has a minimum since it opens upward. I’m not sure what is means by C coordinate, but your vertex is at (3,-4) and lime of symmetry is at x=3.
X intercepts: (1,0) and (5,0)
Y intercept: (0,5)
For a better understanding of the explanation provided here, please find the diagrams in the two files that have been attached.
As can be clearly seen from the diagram, PR and QS are the diameters of the circle and they intersect each other at the centre, O of the circle.
The angle these diameters make at the point of intersection O is 90 degrees.
If Margot joins the points P,Q,R and S which are on the circumference of the circle, then we will get a square with sides PQ, QR, RS and SP as shown in the second diagram.
Thus, the correct option is Option A.
Answer:
x= 0 ,
, 
Step-by-step explanation:
Given, equation is
+
=
. →→→ (1)
Now, by cubing the equation on both sides, we get
(
+
)³ = (
)³
⇒ (15x-1) + (13x+1) + 3×
×
(
+
) = 64 x.
⇒ 28x + 3×
×
(
) = 64x.
(since from (1),
+
=
)
⇒ 12×
×
(
)= 36x.
⇒ 3x =
.
Now, once again cubing on both sides, we get
(3x)³ = (
)³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x =
; x = 
therefore, solution is x= 0 ,
, 