Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
Answer:
B is a convex polygon cause it points out
<h2>3</h2>
Step-by-step explanation:
The equation of line passing through the two points is 
When substituted,the equation becomes 
which when simplified is 
The line clearly passes through origin.
The distance between two points is 
Distance between origin and
is
.
Distance between origin and
is 
Scale factor is 
So,scale factor is 
which when simplified becomes 3.
Answer:
36 and 49
Step-by-step explanation:
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