Answer:
Yes, P(A) = P(A|B)
Step-by-step explanation:
The context of the question is incomplete but I've assumed logically what it might be;
Whether a traveller flies or doesn't fly to their destination is unrelated to whether they home share or not;
Therefore, they are independent;
Independent events are events where the outcome of one event has no effect on the probabilities of the outcomes from a second event;
This can be represented mathematically as: P(A) = P(A|B);
The corollary of this is P(B) = P(B|A);
A common example easily understood would be if you flip a coin, there is a 50% chance of heads and 50% chance of tails;
If I flip and gets a heads first, the probability of getting a heads or tails on the second, third or tenth flip is going to be unchanged, i.e. 50% chance of heads and 50% chance of tails
Answer:
50%.
Step-by-step explanation:
Dado que hay 12 canicas en una bolsa y 6 de ellas son verdes, para determinar la probabilidad de que si se elige una canica al azar, esta sea verde, se debe realizar el siguiente cálculo:
6 / 12 = X
0.5 = X
0.5 = 50/100
50/100 = 50%
Así, hay un 50% de probabilidades de que, eligiendo una canica al azar dentro de la bolsa, la canica elegida sea verde.
Answer:
3. 2/3
Step-by-step explanation:
y=tan(2arctan(1/3))
= 2tan(arctan(1/3))
= 2*1/3
= 2/3
Answer:36
Step-by-step explanation:
Let name the missing angle in the triangle w.
We know that x+z+w=180
We also know that z+w=3z=y.
That means that w=2z.
x=2z, so, 2z+2z+z=180
z=36
