All categories

2 years ago

Please help me idk this

Mathematics

2 answers:

kap26 [50]2 years ago

7 0

Ur answer is 74 degrees

marysya [2.9K]2 years ago

4 0

Answer:

x = 74°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180, that is

x + x + 32 = 180, that is

2x + 32 = 180 ( subtract 32 from both sides )

2x = 148 ( divide both sides by 2 )

x = 74

Thus x = 74°

You might be interested in

Find the y-intercept of the following equation. Simplify your answer.<br><br> y = 10x + 6

hram777 [196]

Answer: 6

Step-by-step explanation:

y = mx + b, where b is the y-intercept, in this case, y-intercept is 6.

3 0

2 years ago

X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of

sladkih [1.3K]

X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125

x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5

3 0

2 years ago

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Given that triangle ABC is a right triangle, select a set of possible side length measurements

Elza [17]

Answer:

4,5,6 / 6,8,10 / 5,12,13 / ....

Step-by-step explanation:

Base on the pythagorean theorem, we have : a² + b² = c².
The first set : 4,5,6 - 4² + 5² = 6² (a possible set)
The second set : 6² + 8² = 10² (another possible set)
The last set : 5² + 12² = 13² (also possible)

There are a lot more sets, but I'll only list 3. Hope this helps :)

3 0

1 year ago

. You invest £4000 in a fund which earns 11% compound return per year. How much would the fund be worth after 10 years, given th

zmey [24]

Answer: $5,678.85

Step-by-step explanation:

First find out how much the fund was worth after 5 years.

Compound interest formula:

= Investment * (1 + rate) ^ years

= 4,000 * ( 1 + 11%)⁵

= £6,740.23

Half was removed:

= 6,740.23/2

= £3,370.12

Then compound this for the remaining 5 years:

= 3,370.12 * (1 + 11%)⁵

= $5,678.85

7 0

2 years ago