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Blababa [14]
3 years ago
12

Trapezoid JKLM is shown on the coordinate plane below: Trapezoid JKLM on the coordinate plane with ordered pairs at J negative 7

, negative 2, at K negative 4, negative 2, at L negative 2, negative 5, at M negative 9, negative 5. If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y − 3), what are the coordinates of point L'? (1, −5) (−10, 6) (−5, 3) (6, −8)
Mathematics
2 answers:
Arisa [49]3 years ago
6 0
The answer is (6, -8). You add 8 to the x coordinate of vertex L and subtract 3 from its y coordinate.
dmitriy555 [2]3 years ago
4 0

Answer:

The correct option is 4.

Step-by-step explanation:

The vertices of trapezoid JKLM are J(-7,-2), K(-4,-2), L(-2,-5), M(-9,-5).

The translation is defined by the rule

(x,y)\rightarrow (x+8,y-3)

The coordinates of point L are (-2,-5), so the coordinates of L' are

L(-2,-5)\rightarrow L'(-2+8,-5-3)

L(-2,-5)\rightarrow L'(6,-8)

The coordinates of L' are (6,-8).

Therefore the correct option is 4.

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-2x + 3y =-9<br> X+y = 2
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Answer:

The values of x and y to the given equation are x=3 and y=-1

The solution to the given equation is (3,-1)

Step-by-step explanation:

Given equations are -2x+3y=-9\hfill (1)

x+y=2\hfill (2)

To solve given equations by using elimination method :

Mutliply the equation (2) into 2 we get

2x+2y=4\hfill (3)

Now adding the equations (1) and (3)

-2x+3y=-9

2x+2y=4

_______________

5y=-5

y-\frac{5}{5}

Therefore y=-1

Now substitute the value of y=-1 in the equation (1) we get

-2x+3(-1)=-9

-2x-3=-9

-2x=-9+3

=-\frac{-6}{-2}

Therefore x=3

The values of x and y to the given equation are x=3 and y=-1

The solution to the given equation is (3,-1)

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Step-by-step explanation:

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