10x^2 - 25 = x^2
Take the square root of each side.
x = 10x - 5i
Answer:
There's no direct variation
Step-by-step explanation:
Required
Determine if there's a direct variation between the number and its position
I'll start by giving an illustration of how the triangle is represented using stars (*)
*
**
***
****
*****
Represent the line number with y and it's position with x
On line 1:
y = 1, x = 1
On line 2:
y = 2, x = 3
On line 3:
y = 3, x = 6
On line 4:
y = 4, x = 10
On line 5:
y = 5, x = 15
Note that, x is gotten by calculating the accumulated number of stars while y is the line number.
Direct variation is represented by
y = kx
Or
kx = y
Where k is the constant of variation
For line 1:
Substitute 1 for y and 1 for x
k * 1 = 1
k = 1
For line 2:
Substitute 2 for y and 3 for x
k * 3 = 2
Divide through by 3
k = ⅔
Note that the values of k in both computations differ.
This implies that there's no direct variation and there's no need to check further.
Answer:
42 cm.
Step-by-step explanation:
Please find the attachment.
Let x be the length of diagonal of the square.
We have been given that length of each side of a square is 30 cm. We are asked to find the length of the diagonal of square to the nearest centimeter.
We can see from our diagram that triangle AC is the diagonal of our square.
Since all the interior angles of a square are right angles or equal to 90 degrees, so we will use Pythagoras theorem to find the length of diagonal.
Upon substituting our given values in above formula we will get,
Let us take square root of both sides of our equation.
Therefore, the length of diagonal of our given square is 42 cm.
4x(3x²+5y) expand by distributing terms
4x*3x²+4x*5y take out the constants
(4*3)xx²+4x*5y simplify 4*3 to 12
12xx²+4x*5y use product rule=xᵃxᵇ=xᵃ+ᵇ, and change the two variables (the x's) into ones, because if there is just one variable with no number by it, then it is a one.
12x¹⁺²+4x*5y and simplify 1+2 to 3.
12x³+4x*5y finally simplify 4x*5y to 20xy
12x³+20xy
Hope this helps, now you know the answer and how to do it. Stay healthy and safe and HAVE A BLESSED AND WONDERFUL DAY! :-)
- Cutiepatutie ☺❀❤
