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3 years ago

In the formula y=mx+b What does the 'm' represent? What does the 'b' represent?

Mathematics

2 answers:

lana [24]3 years ago

7 0

Answer:

The variable b represents the y-intercept, where the line intersects the y-axis.

The variable m represents the rate of change [slope]. The formula for the slope is down below:

$\frac{-y_1 + y_2}{-x_1 + x_2} = m$

This is another way of saying $\frac{rise}{run}$ .

I am joyous to assist you anytime.

Gnoma [55]3 years ago

4 0

In the slope intercept formula

m is the slope ( $\frac{rise}{run}$ )

b is the y-intercept (the y-value of where the line intersects the y-axis)

Hope this helped!

~Just a girl in love with Shawn Mendes

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Which of the following could be the system of nonlinear inequalities graphed below?

Ivan

Answer:

Option A.

Step-by-step explanation:

step 1

we know that

The equation of the solid line is

$y=5$

The solution is the shaded area above the solid line

The equation of the first inequality is

$y\geq 5$

step 2

The equation of the dashed line is

$y=x^{2} -5x+6$

The solution is the shaded area above the dashed line

The equation of the second inequality is

$y>x^{2} -5x+6$

therefore

The system of inequalities could be

$y\geq 5$

$y>x^{2} -5x+6$

4 0

3 years ago

Jason is pulling a box across the room. He is pulling with a force of 19 newtons and his arm is making a 30 angle with the horiz

Cerrena [4.2K]

We are to solve for the vertical and horizontal component of the force he is pulling with.

1. The vertical component of Jason's force is 9.5Newtons.

2.The horizontal component of Jason's force is 2.67Newtons.

3. Therefore, the net force in the vertical direction is -12.5Newtons.

4.Therefore, Resultant, R is 72.11

Question 1:

If Jason is pulling with a force of 19 Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 19 × Sin 30° = 9.5 Newtons.

The vertical component of Jason's force is 9.5 Newtons.

Question 2:

Also,If Jason is pulling with a force of 14 Newtons and his arm is at an angle of 79° with the horizontal.

By resolving Jason's force of pull in the horizontal direction, Fx = 14 × Cos79° = 2.67 Newtons.

The horizontal component of Jason's force is 2.67Newtons.

Question 3:

If Jason is pulling with a force of 23Newtons and his arm is at an angle of 30° with the horizontal.

By resolving Jason's force of pull in the vertical direction, Fy = 23 × Sin 30° = 11.5Newtons.

The vertical component of Jason's force of pull is, 11.5Newtons.

If the box weighs 24Newtons.

By treating up as the +ve vertical direction and down as the -ve vertical direction,

Therefore, the weight of the box acts in the -ve vertical direction, while Jason's vertical force component acts in the +ve vertical direction.

Therefore, the net force in the vertical direction is = 11.5Newtons + (-24Newtons)

Therefore, the net force in the vertical direction is -12.5Newtons.

Question 4:

If there are two forces at right angles to eachother, one of magnitude, 68 and the other of magnitude, 24.

The resultant force on the object can be obtained by Pythagoras theorem (Triangle law of forces).

Resultant, R = √(68²+24²) = √5200.

Therefore, Resultant, R = 72.11

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4 0

3 years ago

Read 2 more answers

(33)(1/9 2−6+2) solve

gregori [183]

(33)(1/9•2-6+2)
18-6+2=14
33•1/14 = 33/14

The answer is 33/14 or 2.35714

4 0

3 years ago

Math problem I need help on

JulijaS [17]

Answer:I think the answer is

1. x=8

Step-by-step explanation:

1. X=8

2. X=1⅓

3. 0x=-12

4. -8x=0

5. 0x=24

8 0

3 years ago

Solve the equation a=m-n for the variable n.

amid [387]

Our objective is to isolate n one side of the equation. The steps are as follows...

a=m-n
(Add n to both sides)
a+n=m-n+n
(The -n and +n cancel out, on the right side of the equation)
a+n=m
(Now subtract a from both sides)
a+n-a=m+a
(The +a and -a cancel out, on the right side of the equation)
n=m+a

7 0

3 years ago

Read 2 more answers