Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Steps to solve:
8j - k + 14; j = 0.25 and k = 1
~Substitute
8(0.25) - (1) + 14
~Simplify
2 - 1 + 14
~Subtract
1 + 14
~Add
15
Best of Luck!
Answer:
1 2/3 = 5/3
6 3/4 = 27/4
-9 7/3 = -34/3
4 2/7 = 30/7
Step-by-step explanation:
Answer:
It is the first answer option.
Step-by-step explanation:
