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Neporo4naja [7]
2 years ago
15

6v *2 + 4v*2  please solve this equation

Mathematics
1 answer:
Kryger [21]2 years ago
8 0

Question

6v²+ 4v²  please solve this equation


Answer:

<h2>10v²</h2>

Step-by-step explanation:

6v²+ 4v² =

(6 + 4)v² =

10v²



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I am donating packages for Christmas drive. After the first week, I spent 126 to donate three children packages and 8 adult pack
anastassius [24]

Answer:

Step-by-step explanation:

Let the price for children and adults package be represented with x and y respectively.

For the first week the sum of the package will be as follows:

3x+8y = 126

For the two weeks after:

6x+4y= 108

So, we will be having two equations

3x+8y = 126..... (1)

6x+4y= 108.......(2)

These are simultaneous equations

From equation 1

3x+8y = 126

3x = 126-8y

X = 126-8y/3 ............. (3)

Put equation 3 into 2

6 ( 126-8y)/3 +4y = 108

756-48y/3 +4y = 108

756-48y+12y/3 = 108

Cross multiplying

756-48y+12y= 108×3

756-48y+ 12y = 324

Collecting like terms

756-324 = 48y-12y

432= 36y

Divide both sides by 36

432/36 = 36y/36

y= 12

Substituting y into equation 1

3x+8= 126

3x+96=126

3x= 126-96

3x= 30

Divide both sides by 3

3x/3 = 30/3

x = 10

Hence for each of the packages for children and adults. It will be 10 and 12 respectively.

8 0
3 years ago
A company loses $5,400 as the result of a manufacturing defect. Each of the 8 owners have agreed to contribute an equal amount,
11Alexandr11 [23.1K]

Answer:

x=$5400:8

$5400:8x = total loss after the owners contribution

7 0
2 years ago
Select the correct answer from each drop-down menu.
podryga [215]

Answer with explanation:

\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}

Average Height of tallest Building in San Francisco

                    =\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8

Average Height of tallest Building in Los Angeles

                    =\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9

→→Difference between Height of tallest Building in Los Angeles and  Height of tallest Building in San Francisco

               =233.9-197.8

               =36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

 |260-197.8|=62.2

 |237-197.8|=39.2

 |212-197.8|=14.2

 |197 -197.8|= 0.8

 |184 -197.8|=13.8

 |183-197.8|=14.8

 |183-197.8|= 14.8

 |175-197.8|=22.8

 |174-197.8|=23.8

 |173 -197.8|=24.8

Average of these numbers

     =\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12

Mean absolute deviation=23.12

5 0
3 years ago
I am a number. I am the
LenaWriter [7]

Answer:

3

Step-by-step explanation:

to find side length of squares take square root of areas

first square side length: 9

second square side length: 6

difference between 9 and 6 is subtraction, 9-6=3

4 0
3 years ago
PLEASE HELP THIS IS DUE SOON &lt;33
ozzi

Answer:

5 inches

Step-by-step explanation:

Theorem states that the smaller two sides of a triangle have to be greater than the biggest side.

The least possible answer would be 5 inches.

6 0
2 years ago
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