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Alexeev081 [22]
3 years ago
15

Hansika paid $9.25 for 2.8 pounds of pretzels. About how much did she pay for a pound of pretzels?

Mathematics
2 answers:
Andrews [41]3 years ago
5 0

Answer:

$3.00

Step-by-step explanation:

Did the quiz & the answer was 3.00!

zlopas [31]3 years ago
4 0
She paid about $4.50. And got back $1.20 back
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It is impossible to get 5 aces when selecting cards from a shuffled deck. Express the indicated degree of likelihood as a probab
lianna [129]

Answer: P(5A) = 0

Step-by-step explanation:

There are four aces in total in a 52 card deck. Therefore the probability of getting 5 aces can be expressed as;

P(5A) = 4/52 × 3/51 × 2/50 × 1/49 × 0/48 = 0

Therefore, it is impossible to get 5 aces from a standard 52 cards deck

8 0
4 years ago
Monday: 10 apples and 5 bananas
goldfiish [28.3K]

Answer:

An apple costs £0.25

A banana costs £0.34

Step-by-step explanation:

5 0
3 years ago
PLZ HELP if u know the answer for sure​
krok68 [10]
The answer is b (-2 5/6)
6 0
3 years ago
Find the product.
4vir4ik [10]
Answer :

6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3 {y}^{3} {z}+3 {y}^{2} {z}^{2}

Step-by-step explanation :

To find the product of

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

First we expand the bracket ,

it implies that, we use the expression outside the bracket to multiply individual expressions inside the bracket.

Hence

3 {y}^{2} z(2 {y}^{2} z + 4yz - y + z)

= 3 {y}^{2} z(2 {y}^{2} z) + 3 {y}^{2} z(4yz) - 3 {y}^{2} z(y )+3 {y}^{2} z( z)

we now apply the law of indices

{a}^{m} \times {a}^{n} = {a}^{m+n}

meaning, when you are multiplying two expressions with the same bases , repeat one of the bases and add the exponents.

Then, simplify to obtain

= 6{y}^{4} {z}^{2} + 12 {y}^{3} {z}^{2}-3{y}^{3} {z}+3 {y}^{2} {z}^{2}
3 0
3 years ago
Which answer describes the calculations that could be used to solve this problem?
faltersainse [42]
D. Since we know that 1 ticket = $8 we would multiply to figure out how much 7 tickets were. (7x$8). And to figure out his change you would subtract the ticket amount from $100 :) Hope this helps
4 0
3 years ago
Read 2 more answers
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