Answer
if it is a question how is this a question
Step-by-step explanation:
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Answer:
- vertical shrink by a factor of 1/3
- shift right 2 units
- shift down 4 units
Step-by-step explanation:
The transformations of interest here are ...
g(x) = k·f(x) . . . . . vertically scale f(x) by a factor of k
g(x) = f(x -h) . . . . shift f(x) right by h units
g(x) = f(x) +k . . . . shift f(x) up by k units
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Working left to right, the first factor we encounter is 1/3, multiplying the value that is cubed. This means the vertical scale factor of f(x) = x^3 is 1/3. A scale factor less than 1 represents a shrink, so ...
transformation #1 = shrink by a factor of 1/3
The next number we encounter is -2 in the factor (x -2)^3. This means h=2 in f(x -h) = (x -2)^3. The horizontal shift right is 2 units:
transformation #2 = right shift 2 units
Finally, we encounter the number -4. This means k=-4 in g(x)=f(x)+k. The up-shift is negative, so ...
transformation #3 = shift down 4 units
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The right- and down-shifts can be done in either order. Here, we have done them as we see them when scanning the equation left-to-right. The vertical scaling must be done before the down-shift, so that it does not affect the amount of down-shift.
Answer:

Step-by-step explanation:
To find the <u>unit rate,</u> we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.
<u>Note:</u> Since the cyclist travels at a <u>constant rate</u>, unitary method can be used.


<u>Divide both sides by 25:</u>



Learn more about unitary method: brainly.com/question/19423643
Answer:
Find the amplitude, period, and horizontal shift. (Assume the absolute value of the horizontal shift is less than the period.)
Step-by-step explanation:
<em>BRAINLIEST?</em>
ANSWER
EXPLANATION
The given equation is

We divide through by 4 to obtain;

This can again be written as:

This is the equation of a circle centered at the origin with radius 4 units.
The graph is shown in the attachment.