All categories

2 years ago

The graph of one complete period of a cosine curve is given.

Mathematics

1 answer:

artcher [175]2 years ago

4 0

Answer:

Find the amplitude, period, and horizontal shift. (Assume the absolute value of the horizontal shift is less than the period.)

Step-by-step explanation:

BRAINLIEST?

You might be interested in

1. Which point on the axis satisfies the inequality y

grigory [225]

Answer:

1) Point $(1,0)$ -----> see the attached figure N $1$

2) The value of x is $4$

3) I quadrant

4) $(1,1)$

5) $y>-5x+3$

Step-by-step explanation:

Part 1)

we know that

If the point satisfy the inequality

then

the point must be included in the shaded area

The point $(1,0)$ is included in the shaded area

Part 2)

we have

$x-2y\geq 4$

see the attached figure N $2$

we know that

The value for x on the boundary line and the x axis is equal to the x-intercept of the line $x-2y= 4$

For $y=0$

Find the value of x

$x-2(0)= 4$

$x=4$

The solution is $x=4$

Part 3)

we have

$x\geq 0$ -----> inequality A

The solution of the inequality A is in the first and fourth quadrant

$y\geq 0$ -----> inequality B

The solution of the inequality B is in the first and second quadrant

the solution of the inequality A and the inequality B is the first quadrant

Part 4) Which ordered pair is a solution of the inequality?

we have

$y\geq 4x-5$

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

we're going to verify all the cases

case A) point $(3,4)$

Substitute the value of x and y in the inequality

$x=3,y=4$

$4\geq 4(3)-5$

$4\geq 7$ ------> is not true

therefore

the point $(3,4)$ is not a solution of the inequality

case B) point $(2,1)$

Substitute the value of x and y in the inequality

$x=2,y=1$

$1\geq 4(2)-5$

$1\geq 3$ ------> is not true

therefore

the point $(2,1)$ is not a solution of the inequality

case C) point $(3,0)$

Substitute the value of x and y in the inequality

$x=3,y=0$

$0\geq 4(3)-5$

$0\geq 7$ ------> is not true

therefore

the point $(3,0)$ is not a solution of the inequality

case D) point $(1,1)$

Substitute the value of x and y in the inequality

$x=1,y=1$

$1\geq 4(1)-5$

$1\geq -1$ ------> is true

therefore

the point $(1,1)$ is a solution of the inequality

Part 5) Write an inequality to match the graph

we know that

The equation of the line has a negative slope

The y-intercept is the point $(3,0)$

The x-intercept is a positive number

The solution is the shaded area above the dashed line

the equation of the line is $y=-5x+3$

The inequality is $y>-5x+3$

3 0

3 years ago

Read 2 more answers

Resuelve el siguiente problema un buzo en una laguna decendio 8m en una hora.Si cada hora bojo la misma cantidad de metros, ¿cua

S_A_V [24]

Answer:

X = 32 meters.

Step-by-step explanation:

Let the unknown distance be X.

Given the following data;

Distance = 8 meters per hour
Time = 4 hours

To find how many meters he would cover in four hours;

1 hour = 8 meters

4 hours = X meters

Cross-multiplying, we have;

X = 8 * 4

X = 32 meters.

7 0

3 years ago

Side c is the hypotenuse. Sides a and b are the legs. 6. b = 6 yd, c = 4 yd. Find the missing side.

balandron [24]

Answer:

2.6666

Step-by-step explanation:

hypotenuse is c^2 so you square 4 to get 16 and then you divide it by 6 to 2.666 so that is the answer for the other leg

7 0

3 years ago

Find the exact value of each expression . Do not use a calculator .

Alex73 [517]

The attached table is one that it is convenient for you to memorize as long as you're taking courses involving angles. For the inverse functions, find the column corresponding to the function, then look for the value in that column. The angle at the beginning of that row is the answer to your question.

8. $\cos^{-1}(0)= 90^{\circ}=\dfrac{\pi}{2}$

9. $\sin^{-1}(1)= 90^{\circ}=\dfrac{\pi}{2}$

10. $\tan^{-1}\left( \dfrac{\sqrt{3}}{3} \right)=30^{\circ}=\dfrac{\pi}{6}$

8 0

3 years ago

Mrs . Kerr is going to pack 9 carrots, 12 crackers, and 18 grapes into lunch boxes. How many of each food item will be in a lunc

Lilit [14]

Answer:

3 carrots, 4 crackers, and 6 grapes.

Step-by-step explanation:

The greatest common factor of 9, 12, and 18 is 3, so we know that we can make at most 3 identical lunchboxes. Now we have to divide each number by 3 to figure out how much of each item is in each lunchbox. 9/3=3, 12/3=4, and 18/3=6 so there will be 3 carrots, 4 crackers, and 6 grapes in each lunchbox.

4 0

3 years ago