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Law Incorporation [45]
4 years ago
13

which represents a quadratic function?f(x) = −8x3 − 16x2 − 4xf (x) = x 2 2x − 5f(x) = 1f(x) = 0x2 − 9x 7

Mathematics
2 answers:
Zielflug [23.3K]4 years ago
3 0
The standard form of a quadratic equation is f(x) = ax^2<span> + bx + c. Looking at the given choices:

</span><span>A. f(x) = −8x^3 − 16x^2 − 4x
B. f(x) = x^2 + 2x − 5
C. f(x) = 1
D. f(x) = 0x^2 − 9x + 7

Among the choices, the only equation that follows the standard form is B.</span>
Trava [24]4 years ago
3 0

Answer:

Option 2 is correct.

Step-by-step explanation:

We have been given three functions:

Quadratic function is the function having degree 2.

Option 1:

f(x)=-8x^3-16x^2-4x

Here the highest power or degree of the function is 3

Hence, it is not quadratic.

Option 2:

f (x)=x^2+2x-5

Here, the degree of the function is 2.

Hence, quadratic.

Option 3:

f(x)=1

There is no degree since, no variable

Hence, not quadratic.

Option 4:

f(x)=0x^2-9x^7

Here, degree of the function is 7

Hence, not quadratic.

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There are 12 boys and 15 girls in your class.Four new students, 3 boys and 1 girl , join your class. Compare the ratio of boys a
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Answer:

4:5 ,15:16

Step-by-step explanation:

divide 12 and 15 by 3 to get 4 and 5

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4 years ago
Multiply and simplify. <br> cos x sin x (sec x + cot x)
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Answer:

cos(x)(cos(arctan(0cos(x)))+isin(arctan(0cos(x)))) = 0

Step-by-step explanation:

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6 0
3 years ago
In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem
Damm [24]

Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) = 0,7120   or 71,2 %

c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055  or P(C) = 20,55 %

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Its false which means it equals to 0 -24=0
7 0
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Read 2 more answers
A=1/2lw solve for w
mrs_skeptik [129]
Solve for w by simplifying both sides of the equation, then isolating the variable
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