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AlekseyPX
3 years ago
9

you are playing a game of scrabble and have 5 a tiles 3e tiles 1 z tile 2 m tiles 3 l tiles, and 1 y tile to choose from, what i

s the probability that you choose e or y on your next draw?
Mathematics
2 answers:
zzz [600]3 years ago
3 0
Since we want either an e tile OR a y tile, then they are not simultaneous. Thus, we add up the probabilities to form our final probability.

The total number of possibilities is: 5 + 3 + 1 + 2 + 3 + 1 = 15, because there are 15 tiles to choose from.

Now, P(e tile) = 3/15 = 1/5
P(y tile) = 1/15

When we add them up, we get: P(e tile or y tile): 3/15 + 1/15 = 4/15
Thus, we have a 4/15 in choosing an E or a Y tile on the next draw.
Hitman42 [59]3 years ago
3 0

There is a 1/3 chance (hope that also helps).

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First, since we must follow PEMDAS, we need to do the operation that is first, which is addition. 

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