Given:
Consider the expression are
1) 
2) ![\sqrt[3]{-8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D)
3) 
4) ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
To find:
The simplified form of each expression.
Solution:
1. We have,


Therefore, the value of this expression is 6.
2. We have,
![\sqrt[3]{-8}=(-8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28%28-2%29%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=(-2)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-2%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{-8}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D-2)
Therefore, the value of this expression is -2.
3. We have,


Therefore, the value of this expression is -10.
4. We have,
![\sqrt[3]{27}=(27)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%2827%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
Therefore, the value of this expression is 3.
Answer:
100
Step-by-step explanation:
possibility of getting 6 in one roll = 1/6
Possibility of getting 6 in 600 rolls = 1/ 6 x 600 = 100
I hope im right!!!
Answer: 13300
========================================
Work Shown:
A = event that it rains
B = event that it does not rain
P(A) = 0.30
P(B) = 1-P(A) = 1-0.30 = 0.70
Multiply the attendance figures with their corresponding probabilities
- if it rains, then 7000*P(A) = 7000*0.30 = 2100
- if it doesn't rain, then 16000*P(B) = 16000*0.70 = 11200
Add up the results: 2100+11200 = 13300
This is the expected value. This is basically the average based on the probabilities. The average is more tilted toward the higher end of the spectrum (closer to 16000 than it is to 7000) because there is a higher chance that it does not rain.
The person she should go to is Melinda
726 to the hundred's is 700
726 to the ten's is 730