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3 years ago

9

PLEASE HELP ON NUMBER 11 TO BE MARKED THE BRAINLIEST

1 answer:

8090 [49]3 years ago

6 0

Answer:

B) 1820

Step-by-step explanation:

10% = 2600 ÷ 10 = 260

30% = 260 x 3 = 780

2600 - 780 = 1820

Hope this helps! :D

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All real numbers less than 69

inna [77]

Answer:

68

Step-by-step explanation:

68 numbers from 1 to less than 69

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3 years ago

a four digit number is randomly chosen. what is the probability that the number chosen is a multiple of 13

Sunny_sXe [5.5K]

Answer:

3.25

Step-by-step explanation:

3.25 because 13/4 equals 3.25

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3 years ago

A) Work out 4 1/7 + 1 1/2

Vesnalui [34]

Answer:

135/14

9 9/14

Step-by-step explanation:

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3 years ago

Read 2 more answers

Ian is going to use a computer at an internet cafe. The cafe charges an initial fee to

sergiy2304 [10]

Answer:

C(t) = 6 + .4t

Step-by-step explanation:

Since there is a constant rate of 6 for the first 5 minutes, that would be a value itself. After that, it would always differ by .4 every minute, making this the function.

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4 years ago

Darren invests $4,500 into an account that earns 5% annual interests. How much will be in the account after 10 years if the inte

Tom [10]

We have been given that Darren invests $4,500 into an account that earns 5% annual interests. We are asked to find the amount in his account after 10 years, if the interest rate is compounded annually, quarterly, monthly, or daily.

We will use compound interest formula to solve our given problem.

$A=P(1+\frac{r}{n})^{nt}$ , where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.

$5\%=\frac{5}{100}=0.05$

When compounded annually, $n=1$ :

$A=4500(1+\frac{0.05}{1})^{1\cdot 10}$

$A=4500(1.05)^{10}$

$A=4500(1.6288946267774414)$

$A=7330.025820498\approx 7330.03$

When compounded quarterly, $n=4$ :

$A=4500(1+\frac{0.05}{4})^{4\cdot 10}$

$A=4500(1.0125)^{40}$

$A=4500(1.6436194634870132)$

$A=7396.28758569\approx 7396.29$

When compounded monthly, $n=12$ :

$A=4500(1+\frac{0.05}{12})^{12\cdot 10}$

$A=4500(1.00416666)^{120}$

$A=4500(1.64700949769)$

$A=7411.542739605\approx 7411.54$

When compounded daily, $n=365$ :

$A=4500(1+\frac{0.05}{365})^{365\cdot 10}$

$A=4500(1.0001369863013699)^{3650}$

$A=4500(1.6486648137656943695)$

$A=7418.9916619456\approx 7419.00$

Since amount earned will be maximum, when interest is compounded daily, therefore, Darren should use compounded daily interest rate.

3 0

3 years ago