Width =3.5, length = 4
Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl
Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w
0 = 2w^2 - 3w - 14
which factors into
(2w - 7) (w + 2)
Solving for w
2w - 7 = 0
2w = 7
w = 3.5
w+2 = 0
w = -2
So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5
Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14
So the width is 3.5 and the length is 4.
You have to use PEMDAS, by multiplying before you add. So when you multiply 5*6, you get 30 and add the remaining 27 to get 57.
Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,
And
We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
To find the y-intercept, set x = 0 \displaystyle x=0 x=0.
Hope this helped brainliest is appreciated
All parallelograms are quadrilateral
