It's a little hard to tell from the gibberish in the choices but let's go with
Answer: 7 + 6yz
which is of second degree in its variables and has two variables. That's two differences than the first three, which are first degree univariate.
Well 300 and 30 ones would be {330} and 30 hundreds and 30 tens would be 3,300 because 30 times 100 equals 3,000 and 30 times 10 equals 300. Hope this helps :}
Answer:
n = -3
Step-by-step explanation:
Let the number be n. Then (2/3)n-4 = 2n.
Solve for n. To accomplish this, start by mult. both sides by 3, to remove the fractional coefficient: 2n - 12 = 6 n, or -12 = 4n. then n = -3 (answer)
Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
Mercury has the greater density than that of Venus .
