Answer:
There is multiple. You didnt give options so heres all of them.
Step-by-step explanation:
6 : 8 9 : 12 12 : 16 15 : 20 18 : 24 21 : 28 24 : 32 27 : 36 30 : 40 33 : 44 36 : 48 39 : 52 42 : 56 45 : 60 48 : 64 51 : 68 54 : 72 57 : 76 60 : 80 63 : 84 66 : 88 69 : 92 72 : 96 75 : 1007 8 : 104 81 : 108 84 : 112 87 : 116 90 : 120 93 : 124 96 : 128 99 : 132 102 : 136 105 : 140 108 : 144 111 : 148 114 : 152 117 : 156 120 : 160 123 : 164 126 : 168 129 : 172 132 : 1761 35 : 180 138 : 184 141 : 188 144 : 192 147 : 196 150 : 200 153 : 204 156 : 208 159 : 2121 62 : 216 165 : 220 168 : 224 171 : 228 174 : 232 177 : 236 180 : 240 183 : 244 186 : 248 189 : 252 192 : 256 195 : 260 198 : 264 201 : 268 204 : 272 207 : 276 210 : 280 213 : 284 216 : 288 219 : 292 222 : 296 225 : 300 228 : 304 231 : 308 234 : 312 237 : 316 240 : 320 243 : 324246 : 328249 : 332252 : 336255 : 340258 : 344261 : 348264 : 352267 : 356270 : 360273 : 364276 : 368279 : 372282 : 376285 : 380288 : 384291 : 388
etc etc
Answer:
280.5 mm^2
Step-by-step explanation:
scale * 25.5 mm = 127.5 mm 1275/25.5 = 5 scale factor
25.5 * 55/5 = 280.5 mm^2
True.
Let p1 and p2 be the two parallel planes. Let n1 be the normal vector of plane p1 (which is a vector perpendicular to the plane). If p2 is parallel to p1, then n1 is also a normal vector for p2.
Let p3 be the third secant plane, and n3 be its normal vector.
The direction vector of the intersection line of two planes is given by the cross products of their normal vectors (this is due to the fact that the cross product of two vectors is orthogonal two both of them, and that the direction vector of the intersection must be orthogonal two both normal vectors). So, the direction vectors of the two lines are:
v1 = n1 × n3
v2 = n1 × n3
The are equal. Hence, the lines are parallel.
:C
: I took the quiz and got the answer correct.
Hope this helps❤️
