What is 2 1/8 as a decimal number?

Plz help <br> People with a strong mind won't ignore

Genrish500 [490]

Answer:

28. (H) 24 ft

30. (F) $\frac{5}{52}$

Step-by-step explanation:

28. A right triangle can be formed, where the length of the cable represents the hypotenuse, and the ground represents the base of the triangle. From the pythagorean theorem,

$a^2 + b^2 = c^2$

where a and b are legs, and c is the hypotenuse of a right triangle.

So

$18^2 + b^2 = 30^2\\b = \sqrt{30^2 - 18^2}\\b = \sqrt{576}\\b = 24$

30. The probability of drawing a red 1 is $\frac{2}{52}$ (a red star 1 or a red heart 1), the probability of drawing a black 3 is $\frac{2}{52}$ (a black triangle 3 or a black circle 3), and the probability of drawing a six of hearts is $\frac{1}{52}$ (since there is only one six of hearts in the entire deck). Since each of the cards is mutually exclusive from one another, the probability of drawing any of them is simply all of their probabilities added together. That is,

$\frac{2}{52} + \frac{2}{52} + \frac{1}{52} = \frac{5}{52}$

6 0

4 years ago

A paper reported that in a representative sample of 282 American teens age 16 to 17, there were 71 who indicated that they had s

elena-s [515]

Answer:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

Step-by-step explanation:

Information provided

n=282 represent the sample selected

X=71 represent the teens indicated that they had sent a text message while driving

$\hat p=\frac{71}{282}=0.252$ estimated proportion of teens indicated that they had sent a text message while driving

$p_o=0.25$ is the value that we want to test

$\alpha=0.01$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if more than a quarter of Americans age 16 to 17 have sent a text message while driving, and the hypothesis are:

Null hypothesis: $p\leq 0.7$

Alternative hypothesis: $p > 0.25$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.252 -0.25}{\sqrt{\frac{0.25(1-0.25)}{282}}}=0.0776$

Decision

The p value for this case is:

$p_v =P(z>0.0776)=0.4691$

Since the p value is higher than the significance level so then we can conclude that we have enough evidence to FAIL to reject the null hypothesis and there is no evidence in order to say that the true proportion of teens more than a quarter of Americans age 16 to 17 have sent a text message while driving is higher than 0.25

8 0

4 years ago

Can snag one help me will mark branliest

taurus [48]

Answer:

20/5

36/2

16/6

10/5

24

Step-by-step explanation:

didnt have the square root on my key board

7 0

3 years ago

F(x) = -4x2 – 7x + 4<br> Find f(-7)

notka56 [123]

Answer:

Step-by-step explanation:

$f(x) = - 4 {x}^{2} - 7x + 4$

To find f(-7) , substitute the value of x that's - 7 into f(x). That is for every x in f(x) replace it with - 7

We have

$f( - 7) = - 4 ({ - 7})^{2} - 7( -7 ) + 4 \\ = 4(49) + 49 + 4 \\ = 196 + 53 \: \: \: \: \: \: \: \: \: \: \:$

We have the final answer as

Hope this helps you

5 0

3 years ago

i have a pair of red earrings and a pair of silver earrings what is the probability that i will get the pair of red earrings

den301095 [7]

1/4 I think bc there are 2 pairs of each and I total there are four earrings solo

3 0

4 years ago